What is the axis of symetry for the function y=-x2+6x-4

May I have help on This question please I’ll award you brainliest

BartSMP [9]

Answer:

The top right answer choice is correct.

2.3 x 12 = 27.6

27.6 > 27.1

Step-by-step explanation:

Well first off, we know that:

1 foot = 12 inches

To compare the two, we first want to covert 2.3 feet into inches.

2.3 x 12 = 27.6 inches

Now that we have our two values, we need to decide which is greater than the other.

27.6 or 27.1

Both values have a decimal that shows tenths. In this problem, 6 tenths is larger than 1 tenth. Therefore:

27.6 inches > 27.1 inches

5 0

3 years ago

Select the correct answer from each drop-down menu.

serious [3.7K]

Answer:

Center: (4,8)

Radius: 2.5

Equation: $(x-4)^2+(y-8)^2=6.25$

Step-by-step explanation:

It was given that; the endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5).

Note that the longest chord is the diameter;

The midpoint of the ends of the diameter gives us the center;

Use the midpoint formula;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

The center is at; $(\frac{4+4)}{2} ,\frac{5.5+10.5}{2}=(4,8)$

To find the radius, use the distance formula to find the distance from the center to one of the endpoints.

The distance formula is;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r=\sqrt{(4-4)^2+(10.5-8)^2}$

$r=\sqrt{0^2+(2.5)^2}$

$r=\sqrt{0^2+(2.5)^2}=2.5$

The equation of the circle in standard form is given by;

$(x-h)^2+(y-k)^2=r^2$

We substitute the center and the radius into the formula to get;

$(x-4)^2+(y-8)^2=2.5^2$

$(x-4)^2+(y-8)^2=6.25$

6 0

3 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

4 0

3 years ago

Trejon rides his bike 2 1/4 miles each day. Which equation can be used to find r, the number of miles he will ride in 8 days?

LiRa [457]

Answer:

you got this sound from the human body for you so much I was wondering what to say I'm sorry I'm not going anywhere you want to go get me on snap now I got you can do this is the best of

8 0

3 years ago

Which graph represents the solution set of the system of inequalities?

lbvjy [14]

<span>{yâ‰¥12x+1y>âˆ’xâˆ’2 is misunderstanding
Pls correct it</span>

5 0

3 years ago