Digital clocks can display how many numbers that are perfect squares
1 answer:
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We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
9514 1404 393
Answer:
P(0, 4), Q(-3, 0)
Step-by-step explanation:
To find the y-coordinate of P, replace x with 0 and solve for y:
3y = 12
y = 4 . . . . . divide by 3
__
To find the x-coordinate of Q, replace y with 0 and solve for x:
-4x = 12
x = -3 . . . . . divide by -4
Then the intercepts are P(0, 4) and Q(-3, 0). The line is drawn through those points for the indicated values of x.
