Answer:
2
Step-by-step explanation:
Plug 4 in for d and 3 in for c
5d-2/3c
5(4)-2/3(3)
Multiply in the numerator and the denominator
20-2/9
Subtract in the numerator
18/9
2
Hope this helps! :)
I’m pretty sure you just solve exactly like that
-7(-2)-1 =13 at least I’m told that \_( •-• )_/
9 numbers of nickels
13 numbers of quarters
Answer:
see below
Step-by-step explanation:
3^-7 x 3^7 = 1
The negative exponents put it in the denominator
1/ 3*3*3*3*3*3*3 * (3*3*3*3*3*3*3) = 1
The 3's cancel leaving
1/1 = 1
1=1
