Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx =
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx =
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Let's set up an equation.
so we know the answer is -13.
1/3 of a number (our variable) can be written as 1/3n.
8 less than that would be subtracting 1/3n by 8
so we have -13 = 1/3n - 8.
To solve:
Add 8 to both sides: -5 = 1/3n
Multiply both sides by 3 (to cancel fraction): -15 = n
You can check by plugging -15 into the equation we made.
To find the <span>percentaje</span> we need to <span>divided</span> the <span>tataol</span> by the amount we end up having.
22.50/19.50=1.15
<span>then</span> we multiply by 100
115%
Then to find the <span>percentaje</span> increase we subtract
115%-100= 15%
So it has an <span>increament</span> of 15%
I don’t know what that is it’s probably 9999999