M=dc/dp=4/6=4/6=2/3
c(p)=2p/3 +b using (6,4)
4=2(6)/3+b
4=4+b, b=0 so
c(p)=2p/3
(the number of cherries needed as a function of the number of pies)
3(2a+1)=-5(a+6)
First expand the brackets.
6a+3=-5a-30
Now add 5a to both sides.
11a+3=-30
Then subtract 3 from both sides.
11a=-33
Finally divide both sides by 11.
a=- 33/11
=-3
Answer: T = 4c + 4t + 3s
Step-by-step explanation:
Stocks contains:
4-legged chairs
4-legged tables
3-legged stools
So, 1 chair has legs = 4
So, c chairs has legs = 4c
1 table has legs = 4
So, t tables has legs = 4t
1 stool has legs = 3
So, s stools has legs = 3s
Let T denotes the total no. of legs
So, the total number of furniture legs in aisle 2 :
T = 4c + 4t + 3s
Answer:
0.41666666, to round up, the answer is 0.42
Step-by-step explanation:
Answer:
No Solutions
Step-by-step explanation:
for |4x -3| + 10 < 2
|4x - 3| < -8
Not possible since absolute value is positive
