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2 years ago

Lesson 11: electricity & magnetism unit test physical science b unit 5: electricity and magnetism (connexus)

1 answer:

5 0

Electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

<h3>What is electricity?</h3>

Electricity is the movement or flow of negatively charged electrons through a suitable conductor where a charge is applied.

Moreover, magnetism is a natural phenomenon caused by the generation/movement of electric charges.

In conclusion, electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.

Learn more on electricity and magnetism here:

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A current of 1.40 a flows in a wire. how many electrons are flowing past any point in the wire per second?

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The current is the quantity of charge Q flowing through a certain point of the wire in a time interval of $\Delta t$ :
$I= \frac{Q}{\Delta t}$

So, by using this relationship and I=1.40 A, we can find the charge passing any point in the wire in 1 second:
$Q=I \Delta t=(1.40 A)(1.0 s)=1.40 C$

To find how many electrons corresponds to this charge, we should divide this value by the charge of a single electron ( $q=1.6 \cdot 10^{-19}C$ ):
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4 years ago

A circuit consists of four 100W lamps

Ksivusya [100]

Complete question is;

A circuit consists of four 100-W lamps connected in parallel across a 230-V supply. Inadvertently, a voltmeter has been connected in series with the lamps. The resistance of the voltmeter is 1500 Ω and that of the lamps under the conditions stated is six times their value then burning normally. What will be the reading of the voltmeter?

Answer:

150.42 V

Explanation:

We are told that the circuit consists of four 100W lamps.

We know that Power is given by the equation;

P = V²/R

Thus;

R = V²/P

Now, we are told that the four lamps are connected in parallel across a 230V supply.

Thus, V = 230 V

So resistance, R = 230²/100

R = 529 Ω

We are told that the resistance of the lamps under the conditions stated is six times their value when burning normally.

Thus, total resistance of each lamp under the conditions = 529 × 6 = 3174 Ω

So, since they are connected in parallel, equivalent resistance for each lamp = 3174/4 = 793.5 Ω

Now, since this resistance is connected in series with the voltmeter resistance of 1500 Ω

Therefore, total circuit resistance = 1500 + 793.5 = 2293.5 Ω

Thus;

circuit current = 230/2293.5 = 0.100283 A

Now, according to Ohm’s law, voltage drop across the voltmeter = 1500 × 0.100283 ≈ 150.42V

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4 years ago

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