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3 years ago

Heat transfer in liquids or gases that happens due to currents of hot and cold is called

Physics

2 answers:

yKpoI14uk [10]3 years ago

3 0

Answer:

Convection

Explanation:

three types of heat transfer

Heat is transfered via solid material (conduction), liquids and gases (convection), and electromagnetical waves (radiation).

Olegator [25]3 years ago

3 0

I learned it to be conduction but i might be wrong sorry

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3 years ago

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Four satellites are in orbit around the Earth. The heights and the masses of

Kaylis [27]

Answer:

satellite B

Explanation:

A .F= G (mM)/r²

B .F= G (2mM)/r² = 2G (Mm)r²

C .F= G (3mM)/(2r)² = ¾G (mM)/r²

D .F= G (4mM)/(2r)² = G (mM)/r²

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2 years ago

HELP!!! 30 POINTS+BRAINLIEST!!!!!QUICK!!

tia_tia [17]

Answer:

A:7.2 $ms^{-1}$

B:14.25 $ms^{-1}$

C:1.45 $sec$

D:10.3 $m$

E:2.9 $sec$

F:20.88 $m$

Explanation:

Let $v$ be the velocity and $\alpha$ be the angle between the velocity and ground.

Question A:

Horizontal component of velocity is given by $vcos(\alpha )$ .

So,horizontal component is $16\times cos(63)=16\times 0.45=7.2ms^{-1}$

Question B:

Vertical component of velocity is given by $vsin(\alpha )$ .

So,vertical component is $16\times sin(63)=16\times 0.89=14.25ms^{-1}$

Question C:

Time required is given by $\frac{\text{vertical component of velocity}}{g}}=\frac{14.25}{9.8}=1.45 seconds$

Question D:

Maximum height is given by $\frac{\text{vertical component of velocity}^{2}}{2g}}=\frac{203.06}{19.6}=10.3m$

Question E:

Time of flight is twice the time required to reach maximum height= $2\times 1.45=2.9 seconds$ .

Question F:

The distance between the player and ball after landing is called range and is given by $\text{horizontal component of velocity}\times \text{time of flight}=$ $7.2\times 2.9=20.88m$

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3 years ago

a train traveling at 72 km/h crosses a platform in 30 seconds what is the length of the platform in meters

Nookie1986 [14]

Answer:????

Explanation:

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3 years ago

A small block is attached to a spring with a spring constant of 85 N/m. When the spring is compressed 0.30 meters and the releas

Pachacha [2.7K]

Answer:

Explanation:

These Hooke's Law problems are tricky. Here's what we need to know that clears up the problem entirely. The final and also the max speed of the block will be reached at the point where the potential energy of the system is 0. So the equation we need, namely,

$KE+PE=\frac{1}{2}kA^2$ can be simplified down to

$KE=\frac{1}{2}kA^2$ and we solve this first for KE:

$KE=\frac{1}{2}(85)(.30)^2$ and, paying NO attention whatsoever to significant digits here (because if you did the answer you get is not one of the choices)

KE = 3.825 J. Now we can use that value of kinetic energy and solve for the speed we need:

$KE=\frac{1}{2}mv^2$ so

$3.825=\frac{1}{2}(.50)v^2$ so

$v=\sqrt{\frac{2(3.825)}{.50} }$ so

v = 3.91 m/s

5 0

2 years ago