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Flura [38]
3 years ago
5

Which type of waves is important to have for a surfer who wants to do aerial maneuvers? A. Plunging waves B. Surging waves C. Or

bital waves D. Spilling waves
Physics
1 answer:
Sladkaya [172]3 years ago
8 0

Aerial maneuvers in surfing demand taking the surfboard into the air. The best type of waves for such maneuvers are:

- the section of a wave coming towards you should be  smaller than the section you are on

- you should try to find closeout sections of waves (  formations that do not allow a tubular ride )

- the wave should be either wedging or bowling in towards you, it should not be a straight wave.

A.PLUNGING WAVES

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light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of
nekit [7.7K]

Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.

A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.

given

Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.

Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is

θ₂ = θ₁ + 90°

   = 31.94° + 90°

   = 1 21.94°

for the first sheet and

Icos²θ₁ = I

I/I₀ = 0.72

θ₁ = cos⁻¹√(0.72)

    = 31.94°

for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.

To know more about light that is polarized, click on the link below:

brainly.com/question/3092611

#SPJ4

8 0
1 year ago
Consider a disk of radius 4.9 cm, having a uniformly distributed charge of +6.1 μC. The value of the Coulomb constant is 8.98755
gayaneshka [121]

Answer:

the electric field is 42.8×10^6 N/C

Explanation:

let k be the coulomb constant, Q be the charge distribution , R be the radius of the disk and x be the distance from the center.

k = 8.98755×10^9 N×m^2/c^2

Q = 6.1×10^-6 C

R = 4.9×10^-2 m

x = 3.1×10^-3 m

5 0
3 years ago
Cuantos protones tiene El Oxígeno
jarptica [38.1K]

Answer:

se me hace que son 8 protones

4 0
3 years ago
Read 2 more answers
Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms
amid [387]

Answer:

a) Work required for air conditioner A = 354.7 J

b) Work required for air conditioner B = 310.3 J

c) The magnitude of the heat deposited outside for conditioner A = 4684.7 J

d) The magnitude of the heat deposited outside for conditioner B = 4640.3 J

Explanation:

In a carnot air conditioner, it operates like a reverse carnot engine; i.e. it removes heat from the cold reservoir (making it colder) and dumps the heat in the hot reservoir (making it hotter)

For a Carnot air conditioner,

Q꜀ is the heat removed from the colder reservoir = 4330 J for both cases

T꜀ is the temperature of the colder reservoir (temperature of the rooms) = 293 K and 296 K for both cases to be considered.

Qₕ is the heat deposited in the warmer reservoir = ? for both cases

Tₕ is the temperature of the hot reservoir (temperature of outside) = 317 K for both cases.

For Carnot air conditioners,

Qₕ = W + Q꜀ (eqn 1)

And

(Qₕ/Tₕ) - (Q꜀/T꜀) = 0 (eqn 2)

Making Qₕ the subject of formula in eqn 2

Qₕ = Tₕ (Q꜀/T꜀)

Substituting this into eqn 1

Tₕ (Q꜀/T꜀) = W + Q꜀

Q꜀ (Tₕ/T꜀) - Q꜀ = W

Q꜀ [(Tₕ - T꜀)/T꜀ ] = W

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ]

For the air conditioner A,

T꜀ = 293 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 293)/293] = 354.7 J

For the air conditioner B,

T꜀ = 296 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 296)/296] = 310.3 J

c) Qₕ = W + Q꜀

For conditioner A,

Qₕ = 354.7 + 4330 = 4684.7 J

For conditioner B,

Qₕ = 310.3 + 4330 = 4640.3 J

8 0
3 years ago
A conducting sphere of radius r1 = 0.21 m has a total charge of Q = 2.9 μC. A second uncharged conducting sphere of radius r2 =
wolverine [178]

Answer:

what is the anser

Explanation:

4 0
3 years ago
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