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Vesnalui [34]
2 years ago
5

Can anyone please help me with the steps

Physics
1 answer:
KIM [24]2 years ago
3 0

Answer:

A) v_average = - 10 km / h,  B)    v = 1.6 m / s, v = 17.6 m / s

Explanation:

A) the average speed is the average speed of a body, if we assume that the direction of going up the hill is positive

    v₁ = 40 km / h

    v₂ = - 60 km / h

the average speed is

         v_average = \frac{v_1 + v_2}{2}

         v_average = ( 40 - 60)/2

         v_average = - 10 km / h

B) in this case they indicate the acceleration a = 3.2 m / s² and the velocity vo = 9.6 m / s

i) the speed for 2.5 s above

         v = v₀ + a t

as the time is earlier

          t = - 2.5 s

we substitute

          v = 9.6 - 3.2 2.5

          v = 1.6 m / s

ii) the velocity for a subsequent time of 2.5 s

          t = 2.5 s

           

we substitute

          v = 9.6 + 3.2 2.5

          v = 17.6 m / s

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erma4kov [3.2K]

Given:

initial angular speed, \omega _{i} = 21.5 rad/s

final angular speed, \omega _{f} = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

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Now, putting the given values in the above formula:

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Therefore, angular acceleration is:

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Mass per unit length=\mu=\frac{m}{l}=2.4 g/m=2.4\times 10^{-3} kg/m

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