Answer:
The car will travel a distance of 17.45 meters.
Explanation:
Given:
Initial velocity
= 0
Final velocity
= 7.6 m/s
Time taken = 4.6 s
Acceleration = (Final velocity - Initial Velocity )/time
![a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%28V_f-Vi%29%7D%7Bt%7D%3D%20%5Cfrac%7B7.6-0%7D%7B4.6%7D%3D1.65%5C%20ms%5E-2)
We have to calculate total distance traveled by the car.
Let the distance traveled be 'd'
Equation of motion:
![d=V_i(t)+\frac{at^2}{2}](https://tex.z-dn.net/?f=d%3DV_i%28t%29%2B%5Cfrac%7Bat%5E2%7D%7B2%7D)
Plugging the values.
⇒![d=V_i(t)+\frac{at^2}{2}](https://tex.z-dn.net/?f=d%3DV_i%28t%29%2B%5Cfrac%7Bat%5E2%7D%7B2%7D)
⇒![d=0+\frac{1.65*(4.6)^2}{2}](https://tex.z-dn.net/?f=d%3D0%2B%5Cfrac%7B1.65%2A%284.6%29%5E2%7D%7B2%7D)
⇒![d=17.45\ m](https://tex.z-dn.net/?f=d%3D17.45%5C%20m)
The car will travel a distance of 17.45 meters for the above case.
734 is the answer for the chronic blood exchange service of new france
Answer:
last option is the correct one
After rolling off the edge of the cliff and falling ' M ' meters down,
the speed of the boulder is
Square root of ( 19.6 M ) .
If M=111 meters, then the speed is <em>46.64 meters per second</em>.
We have known for roughly 500 years that if there's no air resistance,
the mass of the falling object makes no difference, and all objects fall
with the same acceleration, speed, time to splat, etc.