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kotegsom [21]
2 years ago
12

Which statement correctly describes 1 mole of iodine (I₂)

Chemistry
1 answer:
Vika [28.1K]2 years ago
5 0

Answer:

It contains 6.02*10^23 molecules

Explanation:

Please mark Brainliest

Thank you!

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Please help! I'm not a smart 7th grader, on this assignment you write if it's convection, radiation, or conduction, then you wri
sattari [20]
#8 would be radiation
Because of the heat it produces for the air in the home
#9 Conduction
Because it’s preventing physical heat transfer
#10 convection
Because it is stopping the air from rising
#11 Radiation
Because the heat is emitting from the stove and warms him, but not by direct contact
#12 Conduction
Because the heat transfers from the top of the stove to the cats fur.
#13 Conduction
Because the stove under it heats it through contact
#14 I think Radiation
Because the heat warms up the dish through the air in the oven
#15 Radiation
Because the heat is emitting from the fire.
#16 Conduction
Because the blanket is warming you through physical contact.

I’m not completely sure but the is the best I got. Good luck!
6 0
3 years ago
Which of the following is the last step in performing a titration
Alinara [238K]
The final step in a typical titration, that is here an acid base one would be to finally find the concentration of your unknown substance whether that be the acid or the base. The other steps are used before this to come to the correct calculation and conclusion.
7 0
2 years ago
Read 2 more answers
How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

6 0
2 years ago
The average adult heart pumps about 84. mL/s of blood at 72 beats per minute. Suppose you need to calculate how long it would ta
s2008m [1.1K]

Answer:

63.1 seconds.

Explanation:

Hello!

In this case, since the average adult heart pumps 84.0 mL/s of blood, it means 84.0 mL each second, as we have 5300. mL, the following mathematical set up help us to compute the required time:

t=5300.mL*\frac{1s}{84.mL}\\\\t=63.1s

Which is about 1.05 min.

Best regards!

3 0
2 years ago
As the period number increases on the periodic table (moving from the top of the table to the bottom), A. the atomic number incr
natka813 [3]

C) the number of the pricipal energy level containing the outer electrons increases

3 0
3 years ago
Read 2 more answers
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