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amid [387]
3 years ago
14

A 257-ml sample of a sugar solution containing 1.10 g of the sugar has an osmotic pressure of 31.5 mm hg at 39°c. what is the mo

lar mass of the sugar
Chemistry
1 answer:
dem82 [27]3 years ago
5 0
<span>D. sugar changes from white to a light amber color</span>
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In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced if 5
Rufina [12.5K]

Answer:

The full amount (5.00 g) will be dissolved in 1 L of water at 25°C.

Explanation:

The molecular weight (MW) of Vanillin (C₈H₈O₃) is calculated from the chemical formula as follows:

MW(C₈H₈O₃) = (12 g/mol x 8) + (1 g/mol x 8) + (16 g/mol x 3) = 152 g/mol

If 0.070 mol of C₈H₈O₃ are soluble per liter of water at 25°C, the maximum mass that can be dissolved in 1 L is:

0.070 mol x 152 g/mol = 10.64 g

Since 5.00 g is lesser than the maximum amount that can be dissolved (10.64 g), the added amount will be completely dissolved in 1 L of water at 25°C.

7 0
3 years ago
The osmotic pressure of a saturated solution of strontium sulfate at 25 ∘C∘C is 21 torrtorr. Part A What is the solubility produ
USPshnik [31]

Answer

solubility product = 3.18x 10^-7

Explanation:

We were given the pressure in torr then we need to convert to atm for consistency, ten we have

21torr/760= 0.0276315789 atm

21 Torr = .0276315789 atm

P = i M S T

M = P / iRT

Where p is osmotic pressure

T= temperature= 25C+ 273= 298K

for XY vanthoff factor i = 2

S = 0.0821 L-atm / mol K

M = .0276315789 atm / (2)(0.0821 L atm / K mole)(298 K)

M = 0.000564698046 mol/liters

solubility= 0.000564698046 mol/liters

Ksp = [X+][Y-]

Ksp = X^2

Ksp = [Sr^+2] * [SO4^-2]

Ksp = X^2

Ksp = (0.000564698046)^2

Ksp = 3.18883883 × 10-7

Ksp = 3.18x 10^-7

solubility product = 3.18x 10^-7

Therefore, the solubility product of this salt at 25 ∘C∘C is 3.18x 10^-7

7 0
3 years ago
Carly lives in an area with temperatures that are always very warm. Carly also lives in an area that is close to the equator. Wh
mariarad [96]

The answer would be B.

hope this helps,

Trey

3 0
3 years ago
If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w
balu736 [363]

Answer:

25.0 g.

Explanation:

  • From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.
  • <em>So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.</em>
  • <em>Thus, the grams of the dry salt that will be recovered is 25.0 g.</em>

5 0
3 years ago
6. Calculate the mass of an object that has a density of 19.3 g/mL and a volume of 100. mL. (Show Your Work)
Lemur [1.5K]

Answer:

6. mass=1930g

7.64.10ml

Explanation:

6. mass=density time volume

7.volume=mass divide by density

3 0
3 years ago
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