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lina2011 [118]
2 years ago
15

A box contains three types of fruits weighing 58/3 kg in all. If 73/9 kg of these be oranges, 19/6 kg be strawberries, and the r

est be apples, what is the weight of the apples in the box?
Mathematics
1 answer:
liq [111]2 years ago
4 0

Answer:

hi! saya dari Indonesia^^, maaf saya tidak bisa menjawab soal ini^^

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X2+5x=3x+11 and solve by completing the square
Butoxors [25]
x^2+5x=3x+11\\
x^2+2x-11=0\\
x^2+2x+1-12=0\\
(x+1)^2=12\\
x+1=\sqrt{12} \vee x+1=-\sqrt{12}\\
x=-1+2\sqrt3 \vee x=-1-2\sqrt3
7 0
4 years ago
Find the value of . A. 8 B. 32 C. 192 D. 1,536
Tamiku [17]

Answer:

8

Step-by-step explanation:

plz brainliestt

6 0
3 years ago
Read 2 more answers
Can y’all help me with these plz
nalin [4]

Answer:

1)  160 (less than or equal to) 42+65+x      OR      53

2)  2000 (greater than or equal to) 637+x    OR    $1363

3)  1st piece: 5ft

    2nd piece: 10ft

    3rd piece: 6ft

Step-by-step explanation:

1) You must reach at least 160 blankets. Some have already been added, so just add the total to "x"

2) Your brother already spent $637 of 2000 dollars.

3 0
4 years ago
Can someone please explain?
geniusboy [140]

This is an isosceles triangle. The angles at the base are congruent (they have the same measures).

Look at the picture.

We know: The sum of the measures of angles in a triangle is equal 180°.

Therefore we have the equation:

2x-10+2x-10+3x+25=180       <em>combine like terms</em>

(2x+2x+3x)+(-10-10+25)=180

7x+5=180           <em>subtract 5 from both sides</em>

7x=175              <em>divide both sides by 7</em>

x=25

m\angle A=2x-10\to m\angle A=2(25)-10=50-10=40\\\\m\angle C=m\angle A=40\\\\m\angle B=3x+25\to m\angle B=3(25)+25=75+25=100^o

<h3>Answer: D. m∠C = 40</h3>

6 0
3 years ago
What is the area of the composite figure
oksano4ka [1.4K]

Answer:

C

Step-by-step explanation:

To find the area of a composite figure, separate it into the regular parts which make the irregular shape. This shape is composed of a semi-circle and a rectangle. Find the area by finding the area of each shape.

Semi-circle:

The semi-circle has a diameter of 2 + 4 + 2 = 8. The area this figure uses the radius which is half the diameter. The radius is 4. To find the area substitute r = 4 into \pi r^2 = \pi 4^2 = 16\pi. However the semi-circle has a smaller circle cut out of it with radius 2. The area of the smaller circle is \pir^2 = \pi 2^2=4\pi. The semi circle in the shape is the areas subtracted which equals 12π.

Rectangle:

The area of the rectangle is found using A = b*h = 2*5 = 10.

The total area is 12π + 10 meters squared.

5 0
3 years ago
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