Physical fitness is related to our ability to carry out daily tasks without being too tired or sore. This statement is TRUE.
<h3>Further explanation
</h3>
Good physical fitness means that you can perform daily activities, occupations, and sports. This condition will be achieved through good nutrition, regular exercise, and have enough rest.
The benefit of physical activity and exercise can be immediate as well as long-term. Most importantly, regular activity can improve your quality of life.There are four types of physical fitness:
- Cardiovascular exercise: exercises that increase the work of the heart and lungs, such as walking, jogging, step aerobics, swimming, and biking. Cardio activity improves your heart/lung function and muscle mass.
- Muscular strength exercise: this exercise is to build overall strength and muscle mass.
- Joint flexibility exercise: this exercise to help the ability of the muscle group can be stretched or joint can be moved, for example: bending, lifting and driving. Stretching can reduce the risk of injury.
- Muscular endurance exercise: this exercise to find out how many repetitions of exercises a person can perform, such as push-ups and sit-ups.
<h3>Learn more
</h3>
Physical activity brainly.com/question/1400373
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Keywords: physical fitness, the definition of physical fitness, physical activity
Considering the volume of a rectangle, the volume of the tissue box is 3,239.1 cm³.
<h3>What is volume</h3>
Volume is a scalar-type metric quantity that is defined as the extension in three dimensions of a region of space. In other words, the volume corresponds to the space that the shape occupies.
<h3>Volume of a rectangle</h3>
To calculate the volume of a rectangle, it is necessary to multiply its 3 dimensions: length ×width×height. Volume is expressed in cubic units.
<h3>Volume of the tissue box</h3>
In this case, you know:
- Length: 11.8 cm
- Width: 12.2 cm
- Height: 22.5 cm
Replacing in the definition of volume of a rectangle:
Volume of the tissue box= length ×width×height
Volume of the tissue box= 11.8 cm× 12.2 cm× 22.5 cm
Solving:
<u><em>Volume of the tissue box= 3,239.1 cm³</em></u>
Finally, the volume of the tissue box is 3,239.1 cm³.
Learn more about volume:
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Answer:
the magnitude of the force that one particle exerts on the other is 79.08 N
Explanation:
given information:
q₁ = 3.77 μC = -3.77 x 10⁻⁶ C
q₂ = 4.39 μC = 4.39 x 10⁻⁶ C
r = 4.34 cm = 4.34 x 10⁻² m
What is the magnitude of the force that one particle exerts on the other?
lFl = kq₁q₂/r²
= (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶)/(4.34 x 10⁻²)²
= 79.08 N
Answer:
Explanation:
a ) Let let the frictional force needed be F
Work done by frictional force = kinetic energy of car
F x 107 = 1/2 x 1400 x 35²
F = 8014 N
b )
maximum possible static friction
= μ mg
where μ is coefficient of static friction
= .5 x 1400 x 9.8
= 6860 N
c )
work done by friction for μ = .4
= .4 x 1400 x 9.8 x 107
= 587216 J
Initial Kinetic energy
= .5 x 1400 x 35 x 35
= 857500 J
Kinetic energy at the at of collision
= 857500 - 587216
= 270284 J
So , if v be the velocity at the time of collision
1/2 mv² = 270284
v = 19.65 m /s
d ) centripetal force required
= mv₀² / d which will be provided by frictional force
= (1400 x 35 x 35) / 107
= 16028 N
Maximum frictional force possible
= μmg
= .5 x 1400 x 9.8
= 6860 N
So this is not possible.
Check the solution. I hope it helps.. Option D is the correct answer.
