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JulijaS [17]
3 years ago
9

Physical fitness is related to our ability to carry out daily tasks without being too tired or sore. Please select the best answ

er from the choices provided. T F
Physics
2 answers:
WARRIOR [948]3 years ago
7 0

Physical fitness is related to our ability to carry out daily tasks without being too tired or sore. This statement is TRUE.  

<h3>Further explanation </h3>

Good physical fitness means that you can perform daily activities, occupations, and sports. This condition will be achieved through good nutrition, regular exercise, and have enough rest.  

The benefit of physical activity and exercise can be immediate as well as long-term. Most importantly, regular activity can improve your quality of life.There are four types of physical fitness:

  1. Cardiovascular exercise: exercises that increase the work of the heart and lungs, such as walking, jogging, step aerobics, swimming, and biking. Cardio activity improves your heart/lung function and muscle mass.
  2. Muscular strength exercise: this exercise is to build overall strength and muscle mass.
  3. Joint flexibility exercise:  this exercise to help the ability of the muscle group can be stretched or joint can be moved, for example: bending, lifting and driving. Stretching can reduce the risk of injury.  
  4. Muscular endurance exercise:  this exercise to find out how many repetitions of exercises a person can perform, such as push-ups and sit-ups.

<h3>Learn more </h3>

Physical activity brainly.com/question/1400373

Environment factors that affecting physical fitness brainly.com/question/982205

Factors that influence physical fitness brainly.com/question/1488529

Keywords: physical fitness, the definition of physical fitness, physical activity

HACTEHA [7]3 years ago
3 0

Answer:

---------------TRUE-------------------------

Explanation:

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An electron is moving directly toward you in a horizontal path when it suddenly enters a uniform magnetic field that is either v
blagie [28]

Answer:

To your left

Explanation:

The direction of the force exerted on charged particle due to a magnetic field is given by the right-hand-rule, where:

- The index finger indicates the direction of motion of the electron

- the middle finger gives the direction of the magnetic field

- the thumb gives the direction of the force if the particle is positively charged - otherwise, the direction is reversed

in this case, we have an electron (so, a negatively charged particle):

- The direction of motion (index finger) is horizontal, toward you

- The electron begins to curve upward as it enters the field, so this means that the force exerted on the electrons is upward --> the thumb must point downward (because the electron is negatively charged)

- The index finger gives us the direction of the magnetic field: therefore, to your left.

3 0
3 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

5 0
3 years ago
-------------------------------------------------------------------------------
mixas84 [53]

Answer:

nice!!! but did you know that geico can save you 15% or more on car insurance!

Explanation:

8 0
2 years ago
Read 2 more answers
Interactive Solution 8.29 offers a model for this problem. The drive propeller of a ship starts from rest and accelerates at 2.3
MAXImum [283]

Answer:

Δθ = 15747.37 rad.

Explanation:

  • The total angular displacement is the sum of three partial displacements: one while accelerating from rest to a certain angular speed, a second one rotating at this same angular speed, and a third one while decelerating to a final angular speed.
  • Applying the definition of angular acceleration, we can find the final angular speed for this first part as follows:

       \omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)

  • Since the angular acceleration is constant, and the propeller starts from rest, we can use the following kinematic equation in order to find the first angular displacement θ₁:

       \omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)

  • Solving for Δθ in (2):

       \theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)

  • The second displacement θ₂, (since along it the propeller rotates at a constant angular speed equal to (1), can be found just applying the definition of average angular velocity, as follows:

       \theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)

  • Finally we can find the third displacement θ₃, applying the same kinematic equation as in (2), taking into account that the angular initial speed is not zero anymore:

       \omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)

  • Replacing by the givens (α, ωf₂) and ω₀₂ from (1) we can solve for Δθ as follows:

      \theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)

  • The total angular displacement is just the sum of (3), (4) and (6):
  • Δθ = θ₁ + θ₂ + θ₃ = 5044.12 rad + 7252 rad + 3451.25 rad
  • ⇒ Δθ = 15747.37 rad.
4 0
2 years ago
How did ALS impact Stephen Hawking?
olga nikolaevna [1]

Answer:

Professor Hawking had just turned 21 when he was diagnosed with a very rare slow-progressing form of ALS, a form of motor neurone disease (MND). He was at the end of his time at Oxford when he started to notice early signs of his disease. He was getting more clumsy and fell over several times without knowing why.

Explanation:

none

6 0
2 years ago
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