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Alenkinab [10]
3 years ago
8

A man is pulling a 13-kg sled across a flat, snowy surface. He holds the handle of the sled at a 30° angle with the ground.

Physics
1 answer:
adoni [48]3 years ago
6 0
Check the solution. I hope it helps.. Option D is the correct answer.

You might be interested in
Which quantities define momentum?
grigory [225]

Answer:

A. How much matter an object has, plus the magnitude and direction  of its motion

Explanation:

Momentum is defined as the product of mass by velocity, in the international system of measurements (SI) momentum has the following Units [kg*m/s].

P = m*v

where:

P = momentum Lineal [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Therefore the answer is A) How much matter an object has, plus the magnitude and direction  of its motion

7 0
3 years ago
At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Fi
Nataliya [291]

Answer:

The distance from the charge is 3.35 m.                

Explanation:

Given that,

Electric potential, V = 635 V

Magnitude of electric field, E = 189 N/C

We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :

E=\dfrac{V}{d}

d is the distance from charge

d=\dfrac{V}{E}\\\\d=\dfrac{635}{189}\\\\d=3.35\ m

So, the distance from the charge is 3.35 m. Hence, this is the required solution.

8 0
3 years ago
Why is acceleration called vector quantity
MrRissso [65]
Because it has both magnitude and direction. When an object has positive acceleration, the acceleration occurs in the same direction as the movement of the object.
7 0
3 years ago
An automobile travels on a straight road for 55 km at 20 km/h. It then continues in the same direction for another 60 km at 55 k
Natasha_Volkova [10]

Given :

Speed of automobile for first 55 km , v_1=20\ km/h .

Speed of automobile for first 60 km , v_2=55\ km/h .

To Find :

Average velocity of the full trip .

Solution :

We know , average velocity is given by :

v_{avg}=\dfrac{\text{Total distance covered}}{\text{Total time taken }}

Now , time is given by :

T=\dfrac{D}{v}

So ,

v_{avg}=\dfrac{55+60}{\dfrac{55}{20}+\dfrac{60}{55}}\\\\v_{avg}=29.94\ km/h

Therefore , the average velocity (km/h) of the car during the full 115 km trip is 29.94 km/h .

Hence , this is the required solution .

3 0
3 years ago
if the distance between the two objects is tripled how does this affect the overall strength of the electric force between them
worty [1.4K]
Taking into account the Coulomb's Law: F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}

If the value of "d" is tripled:

<span>F_e = K\cdot \frac{2Q_1\cdot Q_2}{(3d)^2} = K\cdot \frac{Q_1\cdot Q_2}{9d^2} =\bf \frac{F_e}{9}

The new force is nine times smaller.</span>
8 0
3 years ago
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