The only one is 40 6 12 18 24,30,36,42
Plug 50 into y and find x.
5x + 10 (50) = 800
5x + 500 = 800
5x = 800 - 500
5x = 300
x = 300 ÷ 5
x = 60
Answer:
5.3%
Step-by-step explanation:
The final probability is calculated by means of the quotient of the specific combinations and the total of total combinations
Let's start with the specific ones,
First the number of combinations of 4 of the 30 students getting a spot, i.e .:
A combinations are equal to:
nCx = n! / x! * (n-x)!
Replacing:
30C4 = 30! / (4! * 26!) = 27405
Segundo the number of combinations of the other audience members filling the other 4 (8-4) spots n = 110, 140 - 30
110C4 = 110! / (4! * 106!) = 5773185
Now the total combinations of possible 8 contestants from the audience
140C8 = 140! / (8! * 132!) = 2.98 * 10 ^ 12
Finally, the probability is equal to:
P = (30C4 * 110C4) / 140C8
replacing:
P = 27405 * 5773185 / 2.98 * 10 ^ 12
P = 0.053
Therefore the probability is 5.3%
Answer:
The estimated probability that Ginger will eat a a pizza everyday of the week is;
D. 8/10 = 80%
Step-by-step explanation:
The given parameters are;
The frequency with which Ginger buys launch = Everyday
The percentage of the time the cafeteria has pizza out = 80%
The outcome of 0 and 1 = No pizza available
The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available
Therefore, we have the;
Group number
Percentage of time pizza available
1
80%
2
80%
3
80%
4
80%
5
40%
6
100%
7
80%
8
100%
9
80%
10
80%
Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8
The number of runs of simulation = 10 runs
The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)
∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10