The answers are x=4 and y=323/2
1) 40/2x-3=8
Multiply both sides by 2x-3 to get rid of fraction
40= 8(2x-3)
Distribute 8
40= 16x-24
Add 24 to both sides
64=16x
Divide by 16
4=x
2) 2y-3/40=8
Multiply both sides by 40 to red rod of fraction
2y-3=320
Add 3 to both sides
2y= 323
Divide by 2
Y=323/2
Now just describe the differences in solving them
FYI / means fraction, right after the slash is bottom of fraction
Answer:
3 and 9
if f(x)=x^2+13 and g(x)=12x-14
Step-by-step explanation:
So when we are looking for the intersection of two functions, we are trying to figure out when they are the same. When you think same, you should think equal (=).
So we want to find when f(x)=g(x) for x.
f(x)=g(x)

Let's get everything to one side.
Subtracting 12x and adding 14 to both sides.

I'm going to reorder the left hand side and also simplify the 13+14 part:

Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.
Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.
So the factored form of our equation is

Since the product is 0, then at least one of the factors must be 0.
So we want to solve both x-3=0 and x-9=0.
x-3=0 can be solved by adding 3 on both sides. This gives us x=3.
x-9=9 can be solved by adding 9 on both sides. This gives us x=9.
The intersection of f and g happens at x=3 or x=9.
Answer:0.08
0.0818
Step-by-step explanation:
Answer:
no picture given
Step-by-step explanation:
no picture given, so it is impossible to say.
Subtract 8d from both sides
21 = 12d + 5 - 8d
Simplify 12d + 5 - 8d to 4d + 5
21 = 4d + 5
Subtract 5 from both sides
21 - 5 = 4d
Simplify 21 - 5 to 16
16 = 4d
Divide both side by 4
16/4 = d
Simplify 16/4 to 4
4 = d
Switch sides
d = 4
<u>Check answer</u>
8d + 21 =12d + 5
Let d = 4
8 × 4 + 21 = 12 × 4 + 5
Simplify 8 × 4 to 32
32 + 21 = 12 × 4 + 5
Simplify 12 × 4 to 48
32 + 21 = 48 + 5
Simplify 32 + 21 to 53
53 = 48 + 5
Simplify 48 + 5 to 53
53 = 53