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dlinn [17]
3 years ago
15

A constant friction force of 25 Nacts on a 65 kg skier for 20

Physics
1 answer:
Radda [10]3 years ago
3 0

Answer:

The skier's change in velocity is 7.69 meters per second.

Explanation:

The Newton's second law tells force is equal to the change on the linear momentum of a body:

\sum\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}

If we approximate the differential \frac{d\overrightarrow{p}}{dt} to \frac{\Delta\overrightarrow{p}}{\Delta t}:

\sum\overrightarrow{F}=\frac{\Delta\overrightarrow{p}}{\Delta t}

Using that linear momentum is mass times velocity:

\sum\overrightarrow{F}=\frac{m\Delta\overrightarrow{v}}{\Delta t}

Solving for \Delta\overrightarrow{v}:

\Delta\overrightarrow{v}=\frac{\Delta t\sum\overrightarrow{F}}{m}=\frac{(20\,s)(25\,N)}{65\,kg}

\Delta\overrightarrow{v}=7.69\,\frac{m}{s}

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Answer:

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Answer:

The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;

C. Increasing the angle from 25° to 50° will increase the total time spent in the air

Explanation:

The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;

T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}

Where;

T = The time of flight of the projectile = The time spent in the air

u = The initial velocity of the projectile

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g = The acceleration due to gravity ≈ 9.81 m/s²

Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;

Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;

T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}

sin(50°) > sin(25°), therefore, we have;

\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} >   \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}

Therefore;

T₂ > T₁

Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.

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hope it helps

plz mark as brainliest

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