Answer:
2.22m/s
Explanation:
Given parameters:
M1 = 60kg
M2 = 75kg
V1 = 0m/s
V2 = 4m/s
Unknown;
Velocity after collision = ?
Solution:
To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;
M1 V1 + M2 V2 = v(M1 + M2)
So;
60 x 0 + 75 x 4 = v (60 +75)
300 = 135v
v = 2.22m/s
Missing figure: find it in attachment.
Answer:
Force D
Explanation:
In order to answer the question, let's keep in mind that the force of gravity on an object on Earth is the attractive force exerted by the Earth on the object; its direction is always downward (towards the Earth's centre), and its magnitude is given by
F = mg
where m is the mass of the object and g is the acceleration of gravity.
It follows immediately that in the figure, the force of gravity is the only force acting downward: therefore, force D.
The other forces are called:
Force A: thrust (it is the forward force generated by the engines)
Force B: lift (it is the upward produced by the aerodynamics of the wings)
Force C: air resistance (it is the backward force due to the friction between the air and the surface of the plane)
Should be a Polar-Covalent bond.
Answer:
Laterite would be your answer.
Explanation:
I hope this helps!
The answer is false
Thats my far estimation