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3 years ago

Numeria

Physics

2 answers:

Vinil7 [7]3 years ago

5 0

Answer:

hope it helps

plz mark as brainliest

polet [3.4K]3 years ago

3 0

Answer:

<h3> $\boxed{40 \: cm}$ </h3>

Explanation:

Load ( L ) = 800 N

Effort ( E ) = 200 N

Load distance ( LD ) = 10 cm

Effort distance ( ED ) = ?

now, Let's find the effort distance:

$\mathsf{L \times LD = E \times ED}$

Plug the values

$\mathsf{800 \times 10 = 200 \times ED}$

Multiply the numbers

$\mathsf{8000 = 200 \: ED}$

Swipe the sides of the equation

$\mathsf{200 \: ED = 8000}$

Divide both sides of the equation by 200

$\mathsf{ \frac{200 \: ED }{200} = \frac{8000}{200} }$

Calculate

$\mathsf{ED \: = \: 40 \: cm}$

Hope I helped!

Best regards!

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<u>Given:</u>

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(a):

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$\vec A$ = area vector of the coil directed along the normal to the plane of the coil.

$\theta$ = angle between $\vec B$ and $\vec A$ .

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(b):

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3 years ago