A baseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other mov
ements. If the linear velocity of the ball relative to the elbow joint is 22.3 22.3 m/s at a distance of 0.480 0.480 m from the joint and the moment of inertia of the forearm is 0.550 0.550 kg·m2, what is the rotational kinetic energy of the forearm?
2 answers:
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The correct answer to the question is : 9375 N.
CALCULATION:
As per the question, the mass of the car m = 1500 Kg.
The diametre of the circular track D = 200 m.
Hence, the radius of the circular path R =
=
= 100 m.
The velocity of the truck v = 25 m/s.
When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.
Hence, the force acting on the car is centripetal force.
The magnitude of the centripetal force is calculated as -
Force F =
=
= 9375 N. [ANS}
The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.