As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
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Answer:51 Groups
Step-by-step explanation:
60 students + 42 students = 102
102 divided by 2 = 51 Total groups.
I couldn’t figure out d answer to This hope this helped
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
Answer:
No Solutions
Step-by-step explanation:
Step 1:
5x + 9 = 2x + 7 + 3x - 15 Equation
Step 2:
5x + 9 = 5x - 8 Add and Subtract
Step 3:
9 = - 8 Subtract 5x on both sides
Answer:
9 ≠ - 8 9 cannot equal - 8
Hope This Helps :)
