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strojnjashka [21]
2 years ago
13

How much work done if an object is moving to the right and a force of 75. 0n is applied at 125 degrees to the motion while the o

bject travels 7. 50m
Physics
1 answer:
bogdanovich [222]2 years ago
4 0

Answer:

-322.64 J

Explanation:

75 N  * cos 125     *    7.5   =  -322.64 J

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Bits of paper are attracted to an electrified comb or rod, even though they have nonet charge. How is this possible?
SashulF [63]

Explanation:

An electrified comb is charged comb ( let say by running it through the hair) and when it is brought in the proximity of  pieces of paper, the pieces tend to cling to it. This happens because the charged comb induces an opposite charge in the paper pieces and as opposite charges attract each other, the pieces are clinged.

7 0
3 years ago
Richard walks from his home to his school at a constant speed. it takes him 4 min to travel 100 m. which of the following lines
Sindrei [870]

Since his speed is constant,

B.

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3 years ago
Is silver magnetic or not ?
evablogger [386]

Answer:

Yes, but its magnetic power is very weak so its not that noticeable to the average person whos not paying attention.

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2 years ago
An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. the maximum speed of the o
Andreas93 [3]
<span>First of all, the maximum speed occurs when the object passes through the
 equilibrium position

The kinetic energy when the object has this max speed is

K= 1/2 * mass * (1.25 m/s)^2

The potential energy in the spring when the speed is equal to zero

U= 1/2 * k * xmax^2

The maximun force of the spring is

mass*acceleration = k*xmax

m * 6.89 m/s2 = k * xmax
xmax = 6.89* m / k

0.5 * m * 1.56  = 0.5 * k * xmax^2

</span>m * 1.56  =  k * (<span>6.89* m / k )^2 </span>
<span>
1.56 m = 47.47 m^2 / k
m/k = 0.032862

period = 2 *pi*sqrt[m/k]
= 2 pi </span><span>sqrt [ </span><span>0.032862]
= 1.139  s

  A fourth of the period elapses between the instants of max acceleration and maximum speed

= 1/4* period
= 1/4 * </span><span><span>1.139  s </span> = 0.284s </span>






7 0
3 years ago
(3) What is the weight of a 50-kg astronaut (a) on Earth (b) On the Moon ,(g=1.7m/s2), (c) on Mars (g=3.7m/s2) (d)in outer space
artcher [175]

Answer:

a) On Earth

490N

b) On the Moon

85N

c) On Mars

185N

d)in outer space traveling with constant velocity.

0

Explanation:

The weight is defined as:

W = mg (1)

Where m is the mass and g is the gravity

a) On Earth g = 9.8m/s^{2}

Then, equation 1 can be used:

W = (50Kg)(9.8m/s^{2})

W = 490Kg.m/s^{2}

but 1N = Kg.m/s^{2}

W = 490N

Hence, the weight of the astronaut on Earth is 490N

b) On the Moon g = 1.7m/s^{2}

W = (50Kg)(1.7m/s^{2})

W = 85N

Hence, the weight of the astronaut on the Moon is 85N

c) On Mars g = 3.7m/s^{2}

W = (50Kg)(3.7m/s^{2})

W = 185N

Hence, the weight of the astronaut on Mars is 185N

(d) in outer space traveling with constant velocity.

Tanking into consideration that the astronaut is traveling in outer space at a constant velocity, it can be concluded that the acceleration will be zero.

Remember that the acceleration is defined as:

a = \frac{v_{f} - v_{i}}{t}

Since the acceleration is the variation of the velocity in a unit of time.

Therefore, from equation 1 is gotten.      

W = (50kg)(0)

Remember that g is the acceleration that a body experience as a consequence of the gravitational field.

 

W = 0

5 0
3 years ago
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