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strojnjashka [21]
2 years ago
13

How much work done if an object is moving to the right and a force of 75. 0n is applied at 125 degrees to the motion while the o

bject travels 7. 50m
Physics
1 answer:
bogdanovich [222]2 years ago
4 0

Answer:

-322.64 J

Explanation:

75 N  * cos 125     *    7.5   =  -322.64 J

You might be interested in
7-10/2<br><br> A.2<br> B.-13<br> C.12
vagabundo [1.1K]

=7-10/2

=7- 5

= 2

A. 2

Hope this helps

3 0
4 years ago
Read 2 more answers
Jonah rode his skateboard 350 meters down a straight road at a constant velocity. He skated
Marysya12 [62]

Answer:

250 m/min down the road

Explanation:

Velocity is equivalent to speed but it considers the direction of the object. Velocity is also calculated by dividing the distance travelled by time. Therefore, v=\frac {d}{t} where d and t are distance and time respectively. Given that d is given as 350 m and t is 1.4 s then by substitution v=\frac {350}{1.4}=250 m/min and the direction is down the road.

Velocity is 250 m/min down the road

8 1
3 years ago
Tarnish is produced by a redox reaction that occurs when a metal reacts with
Dvinal [7]

Answer:

Copper atoms lose electrons to sulfur atoms

Explanation:

a p e x (:

6 0
3 years ago
Describe the 3 types of projectiles.
Anna11 [10]

Answer:Although any object in motion through space (for example a thrown baseball, kicked football, fired bullet, thrown arrow, stone released from catapult) are projectiles, they are commonly found in warfare and sports.

Explanation:

7 0
3 years ago
Read 2 more answers
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude
Pani-rosa [81]
The amplitude of a wave corresponds to its maximum oscillation of the wave itself. 
In our problem, the equation of the wave is
y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,
y(x,t)=0.750 cm
and therefore this value corresponds to the amplitude of the wave.
4 0
3 years ago
Read 2 more answers
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