The video called “SOH CAH TOA: how to solve a right triangle.”
This is explained very well. Make sure you write down the “equations” of SOH CAH and TOA. It helps a lot to be able to go back and plug in from the equation.
Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
Answer:
b) 0.1 mm
Explanation:
Given that
E= 1 x 10¹⁰ N/m²
F= 4 N
d= 0.5 mm
L = 60 mm
We know that elongation due to force F given as
ΔL = 0.12 mm
Therefore the answer is -
b) 0.1 mm
i assume it will be 5mins i hope thi shelp u out
The best statement would be number 3. Sound waves move perpendicular to the medium particles.
