Ask question

Ask question

All categories

4 years ago

14

Which would increase the rate of dissolving salt into water? low temperature little to no agitation more surface area darker col

ors

1 answer:

liq [111]4 years ago

8 0

Answer:

the answer is more surface area

Explanation:

i took the quiz and got it right

You might be interested in

Assume your sampling frequency (fs) is 500 Hz. If you want to capture the 50Hz signal for 5 seconds, calculate the number of sam

belka [17]

Answer:

N = 2500

Explanation:

By definition, the sampling frequency (fs) is:

$f_{s} = N / T$

<em>where N: is the number of samples and T: is the time</em>

Hence, the number of samples at the sampling frequency, 500 Hz, to get 5 seconds of data is:

$N = f_{s} \cdot T = 500 s^{-1} \cdot 5 s = 2500$

I hope it helps you!

3 0

4 years ago

1. A child sitting 1.2 m from the center of a merry-go-round moves with a speed of 1.1 m/s.

Ne4ueva [31]

Answers:

A) $1m/s^{2}$

B) 22. 5 N

Explanation:

A) Since this situation is related to uniform circular motion, the centripetal acceleration $a_{C}$ of the child is calculated by:

$a_{C}=\frac{V^{2}}{r}$

Where:

$V=1.1 m/s$ is the speed

$r=1.2 m$ is the child's distane to the center (the radius)

Hence:

$a_{C}=\frac{(1.1 m/s)^{2}}{1.2 m}$

$a_{C}=1.008 m/s^{2} \approx 1 m/s^{2}$

B) Knowing th centripetal acceleration and the mass $m=22. 5 kg$ of the child, we can calculate the net horizontal force $F$ by:

$F=m a_{C}$

$F=(22. 5 kg)(1 m/s^{2})$

$F=22. 5 N$

4 0

3 years ago

An electric motor has an effective resistance of 22 22 and an inductive reactance of 72 12 when working under load. The voltage

Alecsey [184]

Answer:

Current amplitude, I = 5.57 A

Explanation:

It is given that,

Effective resistance, R = 22 ohms

Inductive reactance, L = 72 ohms

Voltage of the alternating source, V = 420 volt

The total impedance of the RL circuit is given by :

$Z=\sqrt{R^2+L^2}$

$Z=\sqrt{(22)^2+(72)^2}$

Z = 75.28 ohms

From Ohm's law,

$V=I\times Z$

$I=\dfrac{V}{Z}$

$I=\dfrac{420}{75.28}$

I = 5.57 A

So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.

6 0

4 years ago

Write the nuclear equation for the alpha decay of astatine-213.

Sonbull [250]

Answer:

hope this helpes!!

Explanation:

plz mark brainliest

7 0

3 years ago

A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan

mariarad [96]

Answer:

d = 9.69 cm

Explanation:

given,

mass of the block = 1.2 Kg

spring force constant(k) = 730 N/m

spring is compressed = d = ?

rough patch width = 5 cm

μ_k = 0.44

work done by friction = energy lost

$\mu_k mg \times x = \dfrac{1}{2}kd^2-\dfrac{1}{2}mv^2$

$0.44\times 1.2 \times 9.8 \times 0.05 = \dfrac{1}{2}\times 730 \times d^2-\dfrac{1}{2}\times 1.2 \times 2.3^2$

$3.432 = 365 d^2$

$d = \dfrac{3.432}{365}$

d = 0.0969 m

d = 9.69 cm

5 0

3 years ago