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gizmo_the_mogwai [7]
3 years ago
8

How do greenhouse gases such as CO2 and N2O contribute to an increase in Earth’s atmospheric temperature?

Physics
2 answers:
EastWind [94]3 years ago
4 0

Answer:

By trapping the excess heat in the Earth's Atmosphere

Explanation:

When Sun light and other radiations fall on Earth a part of it is reflected back. Greenhouse gases such as CO₂ andN₂O traps the reflected heat and maintain the temperature on Earth. This is required to maintain a temperature that is suitable for survival of life. If these gases are not present in the atmosphere, Earth will be too cold to live. At the same time if these gases are present in large amount, they will trap more heat and thus increase the overall temperature of the Earth resulting in Global Warming.

Due to various reasons the amount of such gases has been increasing in our atmosphere in turn increasing Earth's temperature.

konstantin123 [22]3 years ago
3 0
CO2 and N2O keep the energy that gets to Earth from the sun inside the atmosphere. Without greenhouse gases, our planet would be too cold. But due to the recent increase in greenhouse gases, more energy released from the sun is contained in the Earth, heating it up.
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What is an example of situational irony in the excerpt?​
Murrr4er [49]
Which excerpt are you talking about?
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3 years ago
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as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?
GenaCL600 [577]

Answer:

False

Explanation:

A dominant trait is a trait that is inherited from parents. It is a trait that is obtained from a particular copy or type of a gene that overshadows or overwhelms the effects of another type or copy of that gene. Dominant traits are controlled by a single gene.

Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

5 0
3 years ago
3- (a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a
ASHA 777 [7]

Explanation:

a) The Earth makes 1 rotation in 24 hours.  In seconds:

24 hr × (3600 s / hr) = 86400 s

b) 1 rotation is 2π radians.  So the angular velocity is:

2π rad / 86400 s = 7.27×10⁻⁵ rad/s

c) The earth's linear velocity is the angular velocity times the radius:

40075 km × 7.27×10⁻⁵ rad/s = 2.91 km/s

7 0
3 years ago
Diagram B D c с Which car has: Ke = 100 PE=0? * 1 point A B C D​
erma4kov [3.2K]

Answer:

The car C has KE = 100, PE = 0

Explanation:

The principle of conservation of energy states that although energy can be transformed from one form to another, the total energy of the given system remains unchanged.

The energy that a body possesses due to its motion or position is known as mechanical energy. There are two kinds of mechanical energy: kinetic energy, KE and potential energy, PE.

Kinetic energy is the energy that a body possesses due to its motion.

Potential energy is the energy a body possesses due to its position.

From the principle of conservation of energy, kinetic energy can be transformed into potential energy and vice versa, but in all cases the energy is conserved or constant.

In the diagram above, the cars at various positions of rest or motion are transforming the various forms of mechanical energy, but the total energy is conserved at every point. At the point A, energy is all potential, at B, it is partly potential partly kinetic energy, However, at the point C, all the potential energy has been converted to kinetic energy. At D, some of the kinetic energy has been converted to potential energy as the car climbs up the hill.

Therefore, the car C has KE = 100, PE = 0

6 0
3 years ago
Suppose you pour 0.250 kg of 20.0°C water into a 0.600 kg aluminum pan off the stove with a temperature of 173°C. Assume that th
lapo4ka [179]

Answer:

T_f=5.0116^{\circ}C

Explanation:

Given:

  • mass of water, m_w=0.25\ kg
  • initial temperature of water, T_i_w=20^{\circ}C
  • initial temperature of pan, T_i_p=173^{\circ}C
  • mass of pan, m_p=0.6\ kg
  • mass of water evapourated, m_v=0.03\ kg
  • specific heat of water, c_w=4186\ J.kg^{-1}.K^{-1}
  • specific heat of aluminium pan, c_a=900\ J.kg^{-1}.K^{-1}
  • latent heat of vapourization, L=2256000\ J.kg^{-1}

<u>Using the equation of heat:</u>

<em>Here, initially certain mass of water is vapourised first and then the remaining mass of water comes in thermal equilibrium with the pan.</em>

m_p.c_a.(T_{ip}-T_f)=m_v.L+(m_w-m_v).c_w.(T_f-T_{iw})

0.6\times 900\times (173-T_f)=0.03\times 2256000+(0.25-0.03)\times 4186\times (T_f-20)

T_f=5.0116^{\circ}C

5 0
3 years ago
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