To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:
![C_{6}=6*(12.01g)=72.06g](https://tex.z-dn.net/?f=%20C_%7B6%7D%3D6%2A%2812.01g%29%3D72.06g%20)
![H_{12}=12*(1.008g)=12.096g](https://tex.z-dn.net/?f=%20H_%7B12%7D%3D12%2A%281.008g%29%3D12.096g%20)
![O_{6}=6*(15.999g)=95.994g](https://tex.z-dn.net/?f=%20O_%7B6%7D%3D6%2A%2815.999g%29%3D95.994g%20)
Then you add all of them together:
![72.06g+12.096g+95.994g=180.15g](https://tex.z-dn.net/?f=%2072.06g%2B12.096g%2B95.994g%3D180.15g%20)
Therefore, the molar weight of glucose is 180.15 grams.
Answer:
Alkyne
Explanation:
The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.
The answer is A. Has a low pH in solution.
Answer:
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