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Aneli [31]
2 years ago
8

Plsss help i’ll give brainlist

Chemistry
1 answer:
yarga [219]2 years ago
7 0

Answer:

As the temperature of the water increases, the time needed for the dye to spread decreases. This is because the kinetic energy between the liquid particles increases, therefore helping the dye to dissolve and spread throughout the water.

Explanation:

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A 0.0100 M solution of AgNO3 has a concentration of Ag ion equivalent to
qaws [65]

Answer:

0.0100M of AgNO3 contains 0.0100M of Ag+

Explanation:

AgNO3 when ionized yields Ag+ and NO3-. This means that the amount of AgNO3 in solution is equivalent to the amount of Ag+ and NO3- in that same solution.

1M of AgNO3 solution produces 1M of Ag+  

1M of AgNO3 solution produces 1M of NO3-

This occurs because of the complete ionization of AgNO3 in solution, allowing complete dissolution of the compound.

6 0
2 years ago
Which statement is the best example of an object and motion that would make it hard for people to accept Newton’s first law? A r
djverab [1.8K]

Answer:

The best example of an object and motion that would make it hard for people to accept Newtons first law is, "A rolling ball eventully slows down and comes to a stop".

Explanation:

7 0
3 years ago
If you have 2.4L of SO2 gas (at STP) how many moles of sulfur dioxide do you have?
Andru [333]

Answer:

0.107 mole of SO2.

Explanation:

1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).

With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.

This can be obtained as follow:

22.4 L contains 1 mole of SO2.

Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.

Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.

4 0
3 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion:
siniylev [52]

Answer : The reaction rate will be, 1.9\times 10^{-4}M/s

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2HgCl_2(aq)+C_2O_2^{4-}(aq)\rightarrow 2Cl^-(aq)+2CO_2(g)+HgCl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_2^{4-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_2^{4-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b ....(4)

Dividing 1 from 2, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{k(0.164)^a(0.45)^b}{k(0.164)^a(0.15)^b}\\\\9=3^b\\(3)^2=3^b\\b=2

Dividing 3 from 2, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{k(0.164)^a(0.45)^b}{k(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2

Now, calculating the value of 'k' by using any expression.

Putting values in above rate law, we get:

3.2\times 10^{-5}=k(0.164)^1(0.15)^2

k=8.7\times 10^{-3}M^{-2}s^{-1}

Now we have to determine the reaction rate when the concentration of HgCl_2 is 0.135 M and that of C_2O_2^{-4} is 0.40 M.

\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2

\text{Rate}=(8.7\times 10^{-3})\times (0.135)^1\times (0.40)^2

\text{Rate}=1.9\times 10^{-4}M/s

Therefore, the reaction rate will be, 1.9\times 10^{-4}M/s

6 0
3 years ago
Hurry I need the answer asap
olga nikolaevna [1]

Answer:

Heat or electricity in the atmasphere

Explanation:

4 0
2 years ago
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