1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gladu [14]
3 years ago
10

the density of an 18.0 solution of ammonium sulfate is 1.10g/ml. What mass of Ammonium sulfate is required to prepare 275ml of t

his solution
Chemistry
1 answer:
sergejj [24]3 years ago
5 0

Answer:

Therefore, 54.45 g of Ammonium sulphate is required

Explanation:

Molar mass of ammonium sulphate, (NH₄)₂SO₄ = 132 g/mol

Since density of solution is 1.10 g/ml, a 1 mL solution has mass = 1.10 g

275 mL solution will have a mass = 275 * 1.10 = 302.5 g

Since the solution is 18% ammonium sulphate by weight,

mass of ammonium sulphate present in 275 mL solution = 302.5 * 18/100

mass of ammonium sulphate present in 275 mL solution = 54.45 g

Therefore, 54.45 g of Ammonium sulphate is required

You might be interested in
Which phase has the greatest structure
Zina [86]
A the solid.
it’s solid because solid is harder than gas and liquid which makes it a greater structure
8 0
3 years ago
When the molecules of gases are heated, the average kinetic energy of the molecules increases,
serious [3.7K]
True is the answer to this
6 0
3 years ago
A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c
oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

3 0
2 years ago
Given the unbalanced equation: PbCl₂ + Na₂CrO₂ ---> PbCrO₂ + NaCl. When properly balanced, the sum of the balancing coefficie
Veronika [31]

Answer:

A. 2

hope this helps :)

if you need an explanation let me know!!

3 0
2 years ago
What is the total pressure of a container in kpa if the partial pressures are 1.25 atm and 66.7 psi?
STatiana [176]

Answer:

586 kpa(kilopascal/1000 pascals)

Explanation:

given 1.24 atm(standard atmosphere), and 66.7 psi(pound force per square inch).

To find the total pressure we should use dalton's law of partial pressures which is the sum of the pressures of each individual gas.

then we convert them to pascals and divide by 1000 to get the measurement in kilopascal.

knowing that 1 atmosphere is proportional to around 14.696 psi. We can multiply our given measure of atm by that and sum it by psi like so. 1.24×14.6959 = 18.22298.

Then,

18.22298+ 66.7 = 84.92298

psi.

Since 1 psi is proportional to around 6894.76 pascals. 1 psi will be 68.9476 kilopascal. 84.92298 * 6.89476 = 585.523336 ≈ 586

4 0
3 years ago
Other questions:
  • For social science.
    15·2 answers
  • What is another name for homogeneous mixtures other than solution
    5·1 answer
  • 1. What is the frequency of light having a wavelength of 406 nm?
    9·1 answer
  • Question # 4 & 5. help CHEMISTRY
    6·1 answer
  • Order the various instruments used for measuring water in this experiment (balances, graduated cylinders, beaker and pipette) fr
    7·1 answer
  • Which statement supports Newton's first law of motion?
    8·2 answers
  • Which models of the atom does the experimental evidence from Bohr's hydrogen experiment support? Explain why these models are co
    11·1 answer
  • The "Ring of Fire" is a set of _________ that often occur along plate boundaries. There are many plate boundaries along Pacific
    14·1 answer
  • How much CaCO3 would have to be decomposed to produce 247 g of CaO
    6·1 answer
  • The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum ra
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!