Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Seria 5.498 millas
Solo se debe dividir el valor de longitud entre 5280
Answer:
186 Liters at STP conditions
Explanation:
1 mole of any gas at STP conditions occupies 22.4 Liters.
Therefore, 8.32 moles O₂(g) = 8.32 moles x 22.4Liters/mole = 186 Liters (3 sig.figs.)
It has a single valence electron.
3pro & 3ele - it is the single electron in shell 2.
A mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.
<h3>What is concentric hydrochloric acid?</h3>
The concentric hydrochloric acid is used for the analysis of organic and inorganic mixture like lithium chloride, lithium carbonate, and lithium nitrate it releases fumes and cannot be touched with normal hands.
Always use a dropper to use it and for the chemical analysis.
Therefore, mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.
Learn more about concentric hydrochloric acid, here,
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