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Bezzdna [24]
3 years ago
14

Picture below need done by 2:30 thanks, God bless your week

Chemistry
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

1. <u>Evaporation</u> :- The changing of a liquid to a gas.

2. <u>Automobile</u> :- The major source of pollution.

3. <u>Greenhouse</u><u> effect</u> :- Carbon dioxide and water vapour trapping heat gives off by Earth.

4. <u>Ozonosphere</u> :- Layer absorbing ultraviolet rays.

5. <u>Condensation</u> :- The changing of gas to a liquid.

6. <u>Ionosphere</u> :- Layer responsible for reflecting radio waves.

7. <u>Tr</u><u>o</u><u>posphere</u> :- The layer in which weather changes.

Leviafan [203]3 years ago
5 0

1. \sf \bf {\boxed {\mathbb {Evaporation}}} - The changing of liquid to a gas.

2. \sf \bf {\boxed {\mathbb {Automobile}}} - The major source of pollution.

3. \sf \bf {\boxed {\mathbb {Greenhouse \:effect}}} - Carbon dioxide and water vapor trapping heat given off by Earth.

4. \sf \bf {\boxed {\mathbb {Ozonosphere}}} - Layer absorbing ultraviolet rays.

5. \sf \bf {\boxed {\mathbb {Condensation}}} - The changing of a gas to a liquid.

6. \sf \bf {\boxed {\mathbb {Ionosphere}}} - Layer responsible for reflecting radio waves.

7. \sf \bf {\boxed {\mathbb {Troposphere}}} - The layer in which weather changes.

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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How do biologists learn which organisms we're the ancestors of today's plants?
Norma-Jean [14]

by classifying into categories that get smaller and smaller  these are the classification steps :  life , domain , kingdom , phylum , class,  order , family , genus , and species every time you narrow it down the option gets smaller and smaller till there's none left except the species it self .

 

5 0
3 years ago
Why the bond in water molecule os polar covalent bond, while than in chlorine molecule is pure covalent bond? Give reason? ​
erastovalidia [21]

Explanation:

The unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that a water molecule has two poles - a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole (side). We say that the water molecule is electrically polar.

8 0
3 years ago
Calculate the concentration expressed in percent, if 10 g of NaOH is diluted to 500 ml with water.
Zepler [3.9K]

If 10 g of NaOH is diluted to 500 ml with water then  the concentration expressed in percent is 0.5 mol/L .

Calculation ,

Given mass in gram = 10 g

Number of moles = given mass /molar mass = 10 g / 40 g/mol = 0.25mole

Given volume in ml = 500 ml

Given volume in liter  = 0.5 L

Putting the value of mass and volume in equation i we get concentration expressed in percent .

C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L

C  =  0.5 mol/L

Concentration of solution in terms of percentage can be expressed in two ways

1) percentage by mass

2) percentage by volume

Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.  

To learn more about concentration please click here ,

brainly.com/question/10380236

#SPJ4

5 0
1 year ago
We might think of a porous material as being a composite wherein one of the phases is a pore phase. Estimate upper and lower lim
eduard

Answer:

The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are

Ku = 38.252 W/mK

K lower = 0.199 W/mK

Explanation:

As we know  

Ku = Vp * Kair + Vmagnesium * K metal  

Ku = 0.10 *0.02 + (1-0.25) * 51

Ku = 38.252 W/mK

The lower limit  

K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)

K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)

K lower = 0.199 W/mK

8 0
3 years ago
a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what
jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in liters.

n - Molar quantity, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}} (2)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in liters.

T_{1}, T_{2} - Initial and final temperature, measured in Kelvin.

If we know that P_{1} = 121\,kPa, P_{2} = 202\,kPa, V_{1} = 2.7\,L, T_{1} = 288\,K and T_{2} = 303\,K, the final volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}

V_{2} = 1.702\,L

The gas will occupy a volume of 1.702 liters.

6 0
3 years ago
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