Find the area in the shape

Cindy and Zoey work at a store. Both girls earn $6.25 per hour

wolverine [178]

Answer:

Step-by-step explanation:

I think this is your full question, right?

<em>Cindy and Zoey work at a store. Both girls earn $6.25 per hour. During a normal week Cindy works 15 hours and Zoey works 20 hours. The expression 6.25(15) + 6.25(20) can be used to calculate the total amount of money that the girls earned in one week. Which expression shows another way to calculate the amount of money the girls earn in one week? </em>

My answer:

The expression shows another way must be equal to: <em>6.25(15) + 6.25(20) </em>

<=> 6.25 (15+20)

Because both girls earn the same per hour.

8 0

3 years ago

2. Eight cards are marked : (3,4,5,6,7,8,9,10), such that each card has

viva [34]

2. Eight cards are marked : (3,4,5,6,7,8,9,10), such that each card has
exactly one of theses numbers. A card is picked without looking.
Determine the probability of choosing a number greater than 5. (decimal)
A .625
B 1.75
C .50
D .60

The answer is C.

6 0

3 years ago

Answer the question below. Type your response in the

lukranit [14]

<h3>Answer: 31 degrees</h3>

This is because rotations preserve angles. The angle measures won't change. That's why angle BCD is the same as angle B'C'D'. This applies to any rotation (regardless how much you rotate), any translation, any reflection, and any dilation.

Note: dilations will change the side lengths

5 0

3 years ago

Vail Resorts pays part-time seasonal employees at ski resorts on an hourly basis. At a certain mountain, the hourly rates have a

notsponge [240]

Answer:

$z=0.842$

And if we solve for a we got

$\mu=13.16 +0.842*3=15.69$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,3)$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>13.16)=0.20$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20

If we use condition (b) from previous we have this:

$P(X$