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Anna [14]
2 years ago
8

Is Boyle's law universally true? if not mention one of the its limitations​

Chemistry
1 answer:
murzikaleks [220]2 years ago
4 0
Yes because look in the book dh
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How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?
Basile [38]

Answer:

235 g

Explanation:

From the question;

  • Volume is 400.0 mL
  • Molarity of a solution is 4.25 M

We need to determine the mass of the solute K₂CO₃,

we know that;

Molarity = Number of moles ÷ Volume

Therefore;

First we determine the number of moles of the solute;

Moles = Molarity × volume

Moles of  K₂CO₃ = 4.25 M × 0.4 L

                           = 1.7 moles

Secondly, we determine the mass of  K₂CO₃,

We know that;

Mass = Moles × Molar mass

Molar mass of  K₂CO₃, is 138.205 g/mol

Therefore;

Mass = 1.7 moles × 138.205 g/mol

         = 234.9485 g  

         = 235 g

Thus, the mass of  K₂CO₃ needed is 235 g

7 0
3 years ago
What is the name of the ionic compound formed from potassium and iodide?
PSYCHO15rus [73]
I believe it would be KI
8 0
2 years ago
Read 2 more answers
What is the main difference between these two chemical formulas?
Zigmanuir [339]

Answer:

I think it's A

Explanation:

H202 is hydrogen peroxide

H20 is water

7 0
2 years ago
Read 2 more answers
How do you express a number in scientific notation?
kykrilka [37]

D. scientific notation is (insert decimal number) x10^(however many 0's there are)

5 0
3 years ago
The density of mercury is 13.6 g/mL what is the density in lbs/L ( 1 lb hint =0.454 kg )
Vesna [10]

Answer:

30.0\frac{lb}{L}

Explanation:

Hello,

In this case, since 454 g are equivalent to 1 pound and 1000 millilitres are equivalent to 1 liter, the required density is computed below by applying the corresponding conversion factor:

=13.6\frac{g}{mL} *\frac{1lb}{454g} *\frac{1000mL}{1L} \\\\=30.0\frac{lb}{L}

Regards.

6 0
3 years ago
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