Which term labels a solution

Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons?

Sedbober [7]

Answer:

That would be more

Explanation:

5 0

3 years ago

Which compound (s) has(have) a molecular ion at 117 and a peak at 1720 cm-1 in its IR spectrum?

LenaWriter [7]

Answer:

Ethyl Acetate with a chemical configuration of : CH3CO2CH2CH3

Explanation:

Ethyl Acetate has a density of 902 kg/m³, molar mass of 88.11 g/mol and posses a boiling point of 77.1 °C.

It is to be understood that ethyl acetate is the ester of ethanol and it is mostly produced in mass production and most especially used in the production of domestic materials especially materials like glue, efostics and dissolving agent. This is a highly toxic and flammable substance. However colorless and possess a sweet smell, it can be highly poisonous when ingested.

3 0

3 years ago

What is the length of an average solar cycle? A. 5 years B. 11 years C. 22 years D. 10 years

Tems11 [23]

B. A solar cycle usually lasts 11 years.

4 0

2 years ago

Help me please <br> Answer & exp.

nordsb [41]

Explanation:

Some Rules Regarding Oxidation Numbers:

- Hydrogen has oxidation number of + 1 except in hydrides where it is -1

- Oxygen has oxidation number of -2 except in peroxides where it is -1

- Some elements have fixed oxidation numbers. E.g Halogen group elements has oxidation number of -1

- Oxidation number of a compound is the sum total of the individual elements and a neutral compound has oxidation number of 0.

A. HI

Hydrogen has oxidation of + 1

Oxidation number of I:

1 + x = 0

x = -1

B. PBr3

Br has oxidation number of - 1

Oxidation number of Pb:

x + 3 (-1) = 0

x = + 3

C. KH

Hydrogen has oxidation of + 1

Oxidation number of K:

1 + x = 0

x = -1

D. H3PO4

Hydrogen has oxidation number of + 1

Oxygen has oxidation number of -2

Oxidation number of P:

3(1) + x + 4(-2) = 0

3 + x - 8 =0

x = 5

8 0

2 years ago

Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)

Fynjy0 [20]

Answer:

Rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

Explanation:

According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

⇒ $-\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}$ -----------------------------(1)

Given that the rate of disappearance of oxygen = $-\frac{d[O_{2} ]}{dt}$ = 3.64 x 10⁻³ M/s

So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = ?

from equation (1) we can write

$\frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]$

⇒ $\frac{d[SO_{3}] }{dt}$ = 2 x 3.64 x 10⁻³ M/s

⇒ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

7 0

3 years ago