3(v + 2) + 4 = 13
Mutiply the bracket by 3
(3)(v)= 3v
(3)(2)= 6
3v+6+4= 13
3v+10=13
Move +10 to the other side
Sign changes from +10 to -10
3v+10-10= 13-10
3v= 13-10
3v= 3
divide both sides by 3
3v/3= 3/3
v= 1
Answer : v= 1
Answer:
B
Step-by-step explanation:
7mn³|7m²n³ ---14mn^5
| m---2n²
LCM=7mn³×m×2n²
=14m²n^5
or LCM of 7,14 =14
Highest power of m=2
Highest power of n=5
LCM=14m²n^5
Answer:
Part 1) Option A. h(2) = 86.00 means that after 2 seconds, the height of the ball is 86.00 ft
Step-by-step explanation:
we have

where
t ----> is the time in seconds after the ball is dropped
h(t) ----> he height in feet of a ball dropped from a 150 ft
Find h(2)
That means ----> Is the height of the ball 2 seconds after the ball is dropped
Substitute the value of t=2 sec in the equation

therefore
After 2 seconds, the height of the ball is 86.00 ft.
Answer:
x = 10°
Step-by-step explanation:
The diagonals of a rhombus divide the figure into congruent right triangles. That means the two marked acute angles are complementary.
__
<h3>solve for x</h3>
Complementary angles total 90°, so the relation we can use to find x is ...
(3x -13) +(8x -7) = 90
11x = 110 . . . . . . . . . add 20
x = 10 . . . . . . . . . divide by the coefficient of x
The value of x is 10°.
Answer:
-4,-1
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