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lesya692 [45]
2 years ago
10

Compare and contrast electric conductors and electric insulators. Give an example of each.

Physics
2 answers:
ZanzabumX [31]2 years ago
7 0
In physics, any object or material of any type can be broadly classified into either conductors or insulators based on their current carrying properties. There are also materials knows as semiconductors which have some of the properties of conductors.

Explanation

- A conductor is a type of material that allows the flow of charge in one or more directions through its body.
- Electrical current is generated by the flow of electrons, holes, and positive or negative ions in some special cases.
-On the other hand, an insulator is an object or type of material that do not allow the flow of charge through its body.
-Examples of conductors are metals and metallic wires, whereas examples of insulators are dry wood and plastics.

FINAL ANSWER:

A conductor is any material that allows charge to flow through its body while an insulator does not allow charge to flow through its body.
Metals are examples of conductors and dry wood is an example of an insulator.
8090 [49]2 years ago
4 0

Answer:

conductor:-

A substance that allows heat to pass through them is known as a conductor.

Example:-All the metals, water, etc.

Insulator:-

A substance that does not allows heat to pass through them is known as an insulator.

Example:-All the nonmetals etc.

Explanation:

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With a 12 V battery, what is the voltage drop across each resistor?
anzhelika [568]
Call me delusional, but I can't shake the weird hunch that there's supposed to be
a drawing to go along with this question, showing the values of the resistors and
exactly how they're connected to the battery.

In a series circuit, the voltage divides across the resistors in proportion to
their resistances.  If two resistors in series are the only things connected to
your battery, then the voltage across each resistor is . . .

     (12 volts) x (the resistance of that one resistor) / (the sum of both resistors) .
8 0
3 years ago
A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als
Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

V_T = V_1 + V_2

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

V_T = 10 + 10 = \boxed{\text{ D. 20 V}}

6 0
2 years ago
In a simple RC circuit, at t=0 the switch is closed with the capacitor uncharged. If C=30µF, =50V and R=10k, what is the poten
sergij07 [2.7K]

Answer:

Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W

Explanation:

As we know that the current in the circuit at given instant of time is

i = 2.0 mA

R = 10 k ohm

now we know by ohm's law

V = iR

V = (2 mA)(10 kohm)

V = 20 volts

so voltage across the capacitor + voltage across resistor = V

V_c + 20 = 50

V_c = 30 V

Now we know that

U = \frac{q^2}{2C}

here rate of change in energy of the capacitor is given as

\frac{dU}{dt} = \frac{q}{C} \frac{dq}{dt}

\frac{dU}{dt} = (30)(2 mA)

\frac{dU}{dt} = 0.06 W

3 0
3 years ago
Suppose that a wind is blowing in the direction S45°E at a speed of 30 km/h. A pilot is steering a plane in the direction N60°E
Kay [80]

Answer:

The true course: 40.29^\circ north of east

The ground speed of the plane: 96.68 m/s

Explanation:

Given:

  • V_w = velocity of wind = 30\ km/h\ S45^\circ E = (30\cos 45^\circ\ \hat{i}-30\sin 45^\circ\ \hat{j})\ km/h = (21.21\ \hat{i}-21.21\ \hat{j})\ km/h
  • V_p = velocity of plane in still air = 100\ km/h\ N60^\circ E = (100\cos 60^\circ\ \hat{i}+100\sin 60^\circ\ \hat{j})\ km/h = (50\ \hat{i}+86.60\ \hat{j})\ km/h

Assume:

  • V_r = resultant velocity of the plane
  • \theta = direction of the plane with the east

Since the resultant is the vector addition of all the vectors. So, the resultant velocity of the plane will be the vector sum of the wind velocity and the plane velocity in still air.

\therefore V_r = V_p+V_w\\\Rightarrow V_r = (50\ \hat{i}+86.60\ \hat{j})\ km/h+(21.21\ \hat{i}-21.21\ \hat{j})\ km/h\\\Rightarrow V_r = (71.21\ \hat{i}+65.39\ \hat{j})\ km/h

Let us find the direction of this resultant velocity with respect to east direction:

\theta = \tan^{-1}(\dfrac{65.39}{71.21})\\\Rightarrow \theta = 40.29^\circ

This means the the true course of the plane is in the direction of 40.29^\circ north of east.

The ground speed will be the magnitude of the resultant velocity of the plane.

\therefore Magnitude = \sqrt{71.21^2+65.39^2} = 96.68\ km/h

Hence, the ground speed of the plane is 96.68 km/h.

5 0
3 years ago
Consider and mass of a material​
Leni [432]

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Explanation:

3 0
3 years ago
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