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3 years ago

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A gas is stored in a cylinder at a pressure of 6.0x10^5 N/m^2 and at a temperature of 10°C will be the change of the volume of t

he gas at 35° C if the pressure of the gars does not change?

1 answer:

Setler [38]3 years ago

4 0

Answer:

0.34 x 10^-3 m^3

Explanation:

P1 = 6 x 10^5 N/m^2

T1 = 10 degree C = 10 + 273 = 283 K

T2 = 35 degree c = 35 + 273 = 308 K

Pressure remains constant , P2 = P1

P1 V1 = R T1

V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3

Now, let the Volume is V2

P1 V2 = R T2

V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3

Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3

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A child on a sled is perched at the top of a hill, at a height 7.0 m above the base of the hill. The total mass of the girl plus

spin [16.1K]

Answer:

a)11,71 m/s

b)12.73 m/s

Explanation:

We apply the conservation principle because there is no friction between the hill and the sled:

Total initial energy (Ei) = Total initial energy (Ef), Equation(1)

We define:

K = Kinetic energy = $\frac{1}{2}*m*v^{2}$

U = Potential energy = $m*g*h$

m = mass (kg)

v = velocity (m/s)

h = height (m)

g = gravity acceleration = $9.8m/s^{2}$

A) hi=7m, hf=0 ,vi=0 , vf=?

$Ei=Ef\\Ki+Ui=Kf+Uf$

$1/2*m*vi^{2} +m*g*hi= 1/2*m*vf^{2} +m*g*hf$

$0+m*g*hi=1/2*m*vf^{2}+0$

$(2*m*g*hi)/m=vf^{2}$

$vf=\sqrt{2*g*hi}$

$vf=\sqrt{2*9.8*7}$

$vf=11.71 m/s$

Answer: She reaches the base of the hill with speed of 11.22 m/s

B) hi=7 m, vi=5 m/s, hf=0, vf=?

$m*g*hi+1/2*m*vi^{2} =m*g*hf+1/2*m*vf^{2}$

We divide all terms by m

$g*hi+1/2vi^{2} =g*hf+1/2*vf^{2}$

$9.8*7+1/2*5^{2} =1/2*vf^{2}$

$2(68.6+12.5)=vf^{2}$

$162.2=vf^{2}$

$vf=\sqrt{162.2}$

$vf=12.73 m/s$

Answer: She will move with a speed of 12.73 m/s when she reaches the base of the hill

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3 years ago

On a beautiful night in Washington D.C., you see a mirror image of the Washington Monument and surrounding scenery. What causes

Alchen [17]

Your answer would be B, Reflected light! hope this helps

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4 years ago

Read 2 more answers

If a 2000 N force is used to raise a piano at a rate of 10 m/s2, what is the mass of the piano?

saveliy_v [14]

Answer:

To solve this problem we will apply the principle of conservation of energy for which we have that the potential energy on a body, is equivalent to the work done on it at the given point. Therefore we will have the following equality

At the same time we know that work is equivalent to the Force applied over a given distance, so,

The potential energy is equivalent to the product between mass, gravity and height. Recall that the product of mass and gravity is equivalent to weight (The same given in the statement)

Equating,

Then,

Replacing,

Therefore the force needed to lift the piano is 600N

Explanation:

HOPE THIS HELPS!!!

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3 years ago

A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" ac

anyanavicka [17]

Answer:

$a = 4.07 m/s^2$

now his maximum speed is given as

$v = 3a = 12.21 m/s$

Explanation:

Total time for which Usain Bolt accelerated is given as

$t_1 = 3 s$

now the velocity after uniform acceleration is given as

$v_1 = 0 + 3a$

now remaining time for which he run for the finish line is given as

$t_2 = (9.69 - 3) = 6.69 s$

now the distance moved by him during uniform acceleration is given as

$d_1 = \frac{1}{2}a(3^2)$

$d_1 = 4.5 a$

another distance that he moved for uniform speed is given as

$d_2 = (3a)(6.69)$

$d_2 = 20.07 a$

now total distance moved by him is 100 m so we have

$20.07 a + 4.5 a = 100$

$a = 4.07 m/s^2$

now his maximum speed is given as

$v = 3a = 12.21 m/s$

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4 years ago

An object with a height of 4.0 cm is placed 30.0 cm from a lens. The resulting inverted image has a height of 1.5 cm. What is th

jarptica [38.1K]

Answer:

Focal length of the lens is 8.2 cm.

Explanation:

It is given that,

Height of object, h = 4 cm

Object distance, u = -30 cm

Height of the image, h' = -1.5 cm (negative because the image is inverted)

We need to find the focal length of the lens. It can be calculated using lens formula as :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

Magnification, $m=\dfrac{v}{u}=\dfrac{h'}{h}$

$\dfrac{v}{-30}=\dfrac{-1.5}{4}$

Image distance, v = 11.25 cm

$\dfrac{1}{11.25}-\dfrac{1}{-30}=\dfrac{1}{f}$

f = 8.18 cm

or f = 8.2 cm

So, the focal length of the lens is 8.2 cm. Hence, this is the required solution.

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3 years ago