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notka56 [123]
3 years ago
13

A gas is stored in a cylinder at a pressure of 6.0x10^5 N/m^2 and at a temperature of 10°C will be the change of the volume of t

he gas at 35° C if the pressure of the gars does not change?
Physics
1 answer:
Setler [38]3 years ago
4 0

Answer:

0.34 x 10^-3 m^3

Explanation:

P1 = 6 x 10^5 N/m^2

T1 = 10 degree C = 10 + 273 = 283 K

T2 = 35 degree c = 35 + 273 = 308 K

Pressure remains constant , P2 = P1

P1 V1 = R T1

V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3

Now, let the Volume is V2

P1 V2 = R T2

V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3

Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3

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A 650 × 10–4 F capacitor stores 24 × 10–3 of charge.
alexgriva [62]

C. 0.37V. A capacitor of 650x10⁻⁴F that stores 24x10⁻³C has a potential difference of 0.37V between its plates.

The key to solve this problem is using the capacitance equation C = Q/Vᵃᵇ, where C is the capacitance, Q the charge stored in the plates, and Vᵃᵇ the potential difference between the plates.

A 650x10⁻⁴F capacitor stores 24x10⁻³C, clear Vᵃᵇ for the equation:

C = Q/Vᵃᵇ -----------> Vᵃᵇ = Q/C

Solving

Vᵃᵇ = 24x10⁻³C/650x10⁻⁴F = 0.37V

3 0
3 years ago
How is light energy transported?
REY [17]

Answer:

By reflection

Explanation:

The light energy can be transported by the means of transmitting it by reflecting it to several surfaces . as we know , light doesn't need any medium to travel . Electromagnetic waves are used to transmit them .

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Leftover planetesimals that formed in the region of the solar system now occupied by the jovian planets are called
rewona [7]

Answer:

Comets

Explanation:

Comets are planetary celestial bodies consisting of ice and dust, sometimes rocky particles  formed in the region of the solar system. Long-period comets propagate towards the Sun by gravitational perturbations caused by passing stars. Some comets usually hyberbolic comets, move through the inner Solar System  prior to entering the interstellar region. Short period comet lies beyond the orbit of the Neptune.

The Jovian planets include Jupiter, Saturn, Uranus, and Neptune.

Therefore, leftovers of comets (planetesimal bodies) formed in the region of the solar system that are now occupied by the Jovian planets is due to the dusty particles  associated with the comets.

7 0
3 years ago
When two positive charges are brought close together, what happens to the
telo118 [61]

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they will move away from each other

7 0
3 years ago
a solid metal sphere of radius 3.00m carries a total charge of -5.50. what is the magnitude of the electric field at a distance
aivan3 [116]

Answer:

(a) Electric field at 0.250 m is zero.

(b)  Electric field at 2.90 m is zero.

(c) Electric field at 3.10 m is - 5.15 x 10³ V/m.

(d) Electric field at 8.00 m is - 0.77 x 10³ V/m.

Explanation:

Let Q and R are the charge and radius of the solid metal sphere. The solid metal sphere behave as conductor, so total charge Q is on the surface of the sphere.

Electric field inside and outside the metal sphere is :

E = 0 for r ≤ R ( inside )

  = \frac{KQ}{r^{2} } for r > R ( outside )

Here K is electric constant and r is the distance from the center of the metal sphere.

(a) Electric field at 0.250 m is zero as r < R i.e. 0.250 m < 3 m from the above equation.

(b)  Electric field at 2.90 m is zero as r < R i.e. 2.90 m < 3 m from the above equation.

(c) Electric field at 3.10 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 3.10 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{3.10^{2} }

E = - 5.15 x 10³ V/m

(d) Electric field at 8.00 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 8.00 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{8^{2} }

E = - 0.77 x 10³ V/m

8 0
3 years ago
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