3 years ago

Which is a example of application of a scientific concept?

Physics

1 answer:

stira [4]3 years ago

3 0

I think its c or d but im not quite sure.....

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A string that is under 54.0 N of tension has linear density 5.20 g/m . A sinusoidal wave with amplitude 2.50 cm and wavelength 1

kicyunya [14]

Answer:

8.89288275 m/s

Explanation:

F = Tension = 54 N

$\mu$ = Linear density of string = 5.2 g/m

A = Amplitude = 2.5 cm

Wave velocity is given by

$v=\sqrt{\frac{F}{\mu}}\\\Rightarrow v=\sqrt{\frac{54}{5.2\times 10^{-3}}}\\\Rightarrow v=101.90493\ m/s$

Frequency is given by

$f=\frac{v}{\lambda}\\\Rightarrow f=\frac{101.90493}{1.8}\\\Rightarrow f=56.61385\ Hz$

Angular frequency is given by

$\omega=2\pi f\\\Rightarrow \omega=2\pi 56.61385\\\Rightarrow \omega=355.71531\ rad/s$

Maximum velocity of a particle is given by

$v_m=A\omega\\\Rightarrow v_m=0.025\times 355.71531\\\Rightarrow v_m=8.89288275\ m/s$

The maximum velocity of a particle on the string is 8.89288275 m/s

5 0

3 years ago

A boat, whose speed in still water is 2.50 m/s, must cross a 285-m wide river and arrive at a point 118m upstream from where it

son4ous [18]

The figure shows the arrangement of system

The velocity of boat can be resolved in to two

Horizontal component = vcos θ = 2.50 cos 45 = 1.768 m/s

Vertical component = vsin θ = 2.50 sin 45 = 1.768 m/s

Due to horizontal component the boat arrive arrives upstream,

Total horizontal velocity = 1.768 - Vr, where Vr is the velocity of river.

Total time taken to cross the river = width of river/ Vertical component of velocity

t = 285/1.768 = 161.20 seconds

So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds

That is 118 = (1.768-Vr)*161.20

1.768 - Vr =0.732

Vr = 1.036 m/s

So velocity of river flow =1.036 m/s

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3 years ago

Cliff is a postal worker, who placed a 0.60 kg package on a scale, compressing the scale by 0.03 m. What is the force constant o

lesya692 [45]

Hopefully this helps :)

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3 years ago

An object has a mass of 50.0 g and a volume of 10.5 cm3. What is the object's density?

vagabundo [1.1K]

The density is 4.76 gcm^-3
and if mass is in kg then density is equal to 4.76*10^-3

3 0

3 years ago

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ExtremeBDS [4]

Answer:

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2 years ago