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GenaCL600 [577]
3 years ago
6

Which is a example of application of a scientific concept?

Physics
1 answer:
stira [4]3 years ago
3 0
I think its c or d but im not quite sure.....
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A small object is attached to a horizontal spring and set in simple harmonic motion with amplitude A and period T. How long does
Lunna [17]

Answer:

1.5T

Explanation:

Since, the amplitude of SHM is A. So, in one time period T the object will travel travel a distance of 4A.

6A-4A= 2A.

Now, this 2A distance must be traveled in T/2 time period.

So, the total time taken to travel a distance of 6A is T+T/2 = 3T/2 = 1.5T

6 0
3 years ago
A sprinter runs 50m. You are given a stopwatch. Describe how you would measure: 1. the average speed of the sprinter over the en
Oksanka [162]

Answer:

Explanation:

Distance = 50 m

1. To find the average speed, first start the stop watch as the sprinter starts running and then stop it when he reaches the finish line.

Now note the time taken by the sprinter to run for 50 m.

The average speed of the sprinter is defined as the ratio of total distance covered to the total time taken.

Average speed = total distance / total time

2. To find the instantaneous speed, check the seed of the sprinter as he is at the finish line.

6 0
3 years ago
A non-_____ rock has interlocking grains with no specific pattern.
Kazeer [188]
A non <span>foliated </span>rock has interlocking grains with no specific pattern.
3 0
4 years ago
Read 2 more answers
An object is in circular motion. How will the object behave if the centripetal force is removed?
iren2701 [21]
It will be launched in the direction it was going in when the centripetal force is removed

4 0
3 years ago
The 0.41-kg cup of a James Bond anti-Martini-Maker is attached to a spring of spring constant 110 N/m. The cup is displaced hori
ehidna [41]

Answer:

Option B is the correct answer.

Explanation:

Period of a spring is given by the expression

            T=2\pi \sqrt{\frac{m}{k}}

Here, spring constant, k = 110 N/m

         Mass = 0.41 kg

Substituting,

        T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{0.41}{110}}=0.38s

Option B is the correct answer.

5 0
4 years ago
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