Which is a example of application of a scientific concept?

An ice skater spinning with outstretched arms has an angular speed of 5.0 rad/s . She tucks in her arms, decreasing her moment o

Artyom0805 [142]

Answer:

K_{f} / K₀ =1.12

Explanation:

This problem must work using the conservation of angular momentum (L), so that the moment is conserved in the system all the forces must be internal and therefore the torque is internal and the moment is conserved.

Initial moment. With arms outstretched

L₀ = I₀ w₀

the wo value is 5.0 rad / s

final moment. After he shrugs his arms

$L_{f}$ = I_{f} w_{f}

indicate that the moment of inertia decreases by 11%

I_{f} = I₀ - 0.11 I₀ = 0.89 I₀

L_{f} = L₀

I_{f} w_{f} = I₀ w₀

w_{f} = I₀ /I_{f} w₀

let's calculate

w_{f} = I₀ / 0.89 I₀ 5.0

w_{f} = 5.62 rad / s

Having these values we can calculate the change in kinetic energy

$K_{f}$ / K₀ = ½ I_{f} w_{f}² (½ I₀ w₀²)

K_{f} / K₀ = 0.89 I₀ / I₀ (5.62 / 5)²

K_{f} / K₀ =1.12

6 0

3 years ago

Steve was walking down the hallway and smelled something good. He then walked into the room and saw 12 peanut butter cookies on

s2008m [1.1K]

Answer:

binder: Liquid substance used in paint and other media to bind particles of pigment together.

fresco: Where pigments are mixed with water and then applied to a plaster support, usually a wall or a ceiling.

gouache: A type of watercolor in which white pigment is added creating a duller effect, and a tinted feel.

oil: Painting medium where pigments are binded using oils, usually linseed oil.

painting media: Material made of three components; pigment,vehicle, and binder

pigment: Ground up solids that contain color the color in paint.

tempera: A water based painting medium made with egg yolk, often used to paint frescos and panels.

vehicle: Adjusts the viscosity of the paint.

watercolor: Pigment that is mixed with arabic and gum, and mostly water before it is applied to the paper.

Painting Media

Direct Instruction Active

Highlighter

CyanMagentaGreeenClear Highlights

Headphones

Explanation:

6 0

4 years ago

please answer 1-3 and use a separate piece of paper thank you i've been trying those problems for 3 day.... ikr Sad

11Alexandr11 [23.1K]

$\frac{total distance}{ total time}$

$\frac{72m}{36s} = 2m/s$

Same thing for the rest
2) 5km/h
3)360km/h

4 0

4 years ago

Consider helium at 350 K and 0.75 m3/kg. Using Eq. 12-3, determine the change in pressure corresponding to an increase of (a) 1

Alex777 [14]

Answer:

a) $(dP)_{v} = 9.692 kPa$

b) $(dP)_{T} = -9.692 kPa$

c) dP = 0 Pa

Explanation:

The specifies equation is :

$dz = (\frac{\delta z}{\delta x}) _{y} dx + (\frac{\delta z}{\delta y}) _{x} dy$

Note that:

$dP = \frac{R}{v} dT - \frac{RT}{v^{2} } dV$

1% increase in temperature at specific volume:

$dT = \frac{0.01}{1} *350\\dT = 3.5 K$

a) Change in pressure of helium at constant volume:

$(dP)_{v} = \frac{R}{v} dT$

R = 2.0769 kJ/kg-K

dT = 3.5 K

v = 0.75 m³/kg

$(dP)_{v} = \frac{2.0769}{0.75} * 3.5\\(dP)_{v} = 9.692 kPa$

b)

dv = (1%/100%) *0.75

dv = 0.0075 m³/kg

Change in pressure of helium at constant temperature:

$(dP)_{T} = \frac{-RT}{v^{2} } dv$

R = 2.0769 kJ/kg-K

T = 350 K

v = 0.75 m³/kg

dv = 0.0075 m³/kg

$(dP)_{T} = \frac{-(2.0769*350)}{0.75^{2} } *0.0075\\(dP)_{T} = -9.692 kPa$

c) The change in pressure of helium :

$dP = (dP)_{v} + (dP)_{T}$

dP = 9.692 - 9.692

dP = 0

5 0

4 years ago

Megan accelerates her skateboard from 0 m/s to 8 m/s in 2 seconds. What is the magnitude of the acceleration of the skateboard?

iragen [17]

Answer:

chk picture for eqn

Explanation:

5 0

3 years ago