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d1i1m1o1n [39]
3 years ago
5

Why do we see black? Is light being admitted reflected or absorbed or transmitted

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:When white light strikes an object, each individual frequency of light is transmitted, reflected, or absorbed, depending on the properties of the surface molecules. If all frequencies are absorbed by the object, then it appears black. If all frequencies are reflected, then it appears white.

Explanation:

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Elements in the same group/familly of the periodic table are similar in what way
olga nikolaevna [1]
Their chemicals and their reactions, hope I helped
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4 years ago
If the frequency of a wave is 0.25 Hz, what is its period?
aleksandr82 [10.1K]

Answer:

C

Explanation:

frequency = 1 / period

so

frequency = 0.25

0.25 = 1 / period

1 / 0.25 = period

4 s = period

it is not 4 Hz because period is the time taken

so the answer is C

hope this helps ,please mark it

4 0
3 years ago
011 10.0 points
Sedbober [7]
<h2>The temperature of the air is 66.8° C</h2>

Explanation:

From the Newton's  velocity of sound relationship , the velocity of sound is directly proportional to the square root of temperature .

In this case The velocity of sound = frequency x wavelength

= 798 x 0.48 = 383 m/sec

Suppose the temperature at this time = T K

Thus 383 ∝ \sqrt{T}                       I

The velocity of sound is 329 m/s at 273 K ( given )

Thus 329 ∝ \sqrt{273}                   II

Dividing I by II , we have

\frac{383}{329} = \sqrt{\frac{T}{273} }

or \frac{T}{273} = 1.25

and T = 339.8 K  = 66.8° C

4 0
4 years ago
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sergeinik [125]

Answer:

1. geothermal

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4 0
3 years ago
Read 2 more answers
A 55 kg cheerleader uses an oil-filled hydraulic lift to hold four 110 kg football players at a height of 1.0 m. If her piston i
AVprozaik [17]

Answer:

D = 55.2 cm

Explanation:

As we know that the total mass of the all four players is given as

M = 4\times 110

M = 440 kg

diameter of the piston of cheer leader is given as

d_1 = 16 cm

are of cross-section is given as

A_1 = \pi r^2

A_1 = \pi(0.08)^2 = 0.02 m^2

mass of the cheer leader is given as

m = 55 kg

so the pressure due to cheer leader is given as

P_{in} = \frac{mg}{A_1}

P_{in} = \frac{55 \times 9.81}{0.02}

P_{in} = 26835 Pa

Now on the other side pressure must be same

so we have

\frac{Mg}{A} + \rho gH = P_{in}

\frac{440 \times 9.8}{A} + (900)(9.8)(1) = 26835

A = 0.24 m^2

\pi r^2 = 0.24

r = 0.276 m

so diameter on the other side is given as

D = 2 r

D = 55.2 cm

8 0
3 years ago
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