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tamaranim1 [39]
2 years ago
14

The second statement is the of the first.

Mathematics
1 answer:
kipiarov [429]2 years ago
5 0
B is the answer b.converse
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Please could you explain this step by step I’m really stuck.
allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

  • \frac{5}{x + 3} + \frac4{x + 2} = 2
  • 5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)
  • 5 + \frac{4x + 12}{x + 2} = 2x + 6
  • 5(x + 2) +4x + 12 = (2x + 6)(x + 2)
  • 5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12
  • 9x + 22 = 2x^2 + 10x + 12

Let's make one side equal to 0.

  • 0 = 2x^2 + x - 10

Solve by factoring, and then the zero product property.

  • 0 = 2x^2 + x - 10\\

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, ax^2 + bx + c, think two numbers that equal "ac" and add up to "b".

  • 0 = 2x^2 - 4x + 5x - 10
  • 0 = 2x(x - 2) + 5(x - 2)
  • 0 = (2x + 5)(x - 2)

Using the zero product property, set each factor to 0 and solve for x.

  1. 2x + 5 = 0
    2x = -5
    x = -5/2 = -2.5
  2. x - 2 = 0
    x = 2

The two answers are x = -2.5, and x = 2.

3 0
2 years ago
Read 2 more answers
Have another question for you guys it is in the image
Lerok [7]

Answer:

A because its supposed to be on the y axis

5 0
3 years ago
What is the answer plzzzzzz help a kid out
Komok [63]

Answer:

the answer is 8 by one of this question.

4 0
3 years ago
What is the perimeter of the figure?"
maksim [4K]

Answer:

14

Step-by-step explanation:

Perimeter= 4× 3.5 in

=14 in

5 0
3 years ago
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A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the
MrRissso [65]

Answer: The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

Step-by-step explanation:

Given : A kite is being flown at 45^{\circ} . The string of the kite is 120 feet long.  

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}

hence, The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

5 0
3 years ago
Read 2 more answers
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