I’m pretty sure the answer would be B
Answer:
x=21/40
Step-by-step explanation:
First get common denominators
3/8 *5 to top and bottom is now 15/40
3/20 *2 to top and bottom is now 6/40
isolate the X
x-15/40=6/40
+15/40 +15/40
x=21/40
In the given question the length and width of the plot are already given. although there is no direct specification regarding the one that is length or the one that is the width, so it can be taken as your own choice. This will not affect the ultimate answer.
So
Area of the rectangular plot = Length * Width
= 11.7 * 15.4 square cm
= 180.18 square cm
So the area of the rectangular plot as can be seen from the above deduction is 180.18 square centimeter.
The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.
Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars
(not all zero) such that
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which leads to the system of linear equations,

From the third equation, we have
, and substituting this into the second equation gives

and in turn,
. Substituting these into the first equation gives

which tells us that any value of
will work. If
, then
and
. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.
Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.
The surface area is the sum of the are of all sides. One side's area is 64 in^2 and since it's a cube, all sides will be the same.
64*6 = 384
The surface area is 384 in^2