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kow [346]
3 years ago
8

If a sample contains 74.0% of the R enantiomer and 26.0% of the S enantiomer, what is the enantiomeric excess of the mixture?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

The enantiomeric excess of the mixture is 48%

Explanation:

Enantiomeric excess refers to the excess of one enantiomer over the other in a mixture of enantiomers.

Enantiomeric excess = % of major enantiomer (R) - % of minor enantiomer (S)

= 74% - 26% = 48%.

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16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
3 years ago
Read 2 more answers
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kati45 [8]

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Explanation:

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5 0
3 years ago
Which of the following is not equal to 42.7 millimeters?
Stella [2.4K]

The answer is: C. 0.00427 m.

A) 1 km = 1000000 mm.

d = 0.0000427 km · 1000000 mm/km.

d = 47.7 mm.

B) 1 hm = 100000 mm.

d = 0.000427 hm · 100000 mm/hm.

d = 42.7 mm.

C) 1 m = 1000 mm.

d = 0.00427 m · 1000 mm/m.

d = 4.27 mm.

D) 1 cm = 10 mm.

d = 4.27 cm · 10 mm/cm.

d = 42.7 mm.

Millimeter (abbreviated: mm, a thousandth part of metar) is an unit of distance in the metric system.

8 0
3 years ago
The pressure of a 70.0L sample of gas is 600 mm Hg at 20.0C. If the temperature drops to 15.0C and the volume expands to 90.0L,
Mekhanik [1.2K]

Answer:

458.7 mmHg

Explanation:

Step 1:

Data obtained from the question. This includes:

Initial volume (V1) = 70L

Initial pressure (P1) = 600 mmHg

Initial temperature (T1) = 20°C

Final temperature (T2) = 15°C

Final volume (V2) = 90L

Final pressure (P2) =...?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T (°C) + 273

Initial temperature (T1) = 20°C

Initial temperature (T1) = 20°C + 273 = 293K

Final temperature (T2) = 15°C

Final temperature (T2) = 15°C + 273 = 288K

Step 3:

Determination of the new pressure of the gas.

The new pressure of the gas can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

600 x 70/293 = P2 x 90/288

Cross multiply to express in linear form

P2 x 90 x 293 = 600 x 70 x 288

Divide both side by 90 x 293

P2 = (600 x 70 x 288) / (90 x 293)

P2 = 458.7 mmHg

Therefore, the new pressure of the gas is 458.7 mmHg

5 0
3 years ago
All atoms of the same element have the same:
Korvikt [17]
They have the same number of protons
8 0
3 years ago
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