Answer:
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Answer : The half life of 28-Mg in hours is, 6.94
Explanation :
First we have to calculate the rate constant.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = time passed by the sample = 48.0 hr
a = initial amount of the reactant disintegrate = 53500
a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520
Now put all the given values in above equation, we get
Now we have to calculate the half-life.
Therefore, the half life of 28-Mg in hours is, 6.94
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The resistance of the heating element is 21.61 Ω
Given
The power dissipated = 1500 W
Voltage = 180 V
We know that
Power = Voltage * Current
⇒ Power / Voltage = Current
⇒ 1500 W/180 V = Current
⇒ 8.33 A = Current
In order to calculate the resistance of the heating element. We Have to apply the formula
Power = (Current)^2 * Resistance
⇒ Resistance = Power / (Current)^2
⇒ Resistance = 1500 W/ (8.33) ^2
⇒ Resistance = 21.61 Ω
Hence the resistance of the heating element is 21.61 Ω
Learn more about resistance here: -
“ brainly.com/question/17330679 “
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