Answer:
167 kJ
Explanation:
Given parameters
Change in enthalpy = 130 kJ (decrease)
Work done = -137 kJ
Change in energy, \delta = ?
From the first law of thermodynamics:
ΔH = ΔE + PΔV,
Where, ΔH= change in enthalpy
ΔE = change in Internal energy
Substituting values into the above formula —
130 kJ = ΔE + -137 kJ
130 kJ = ΔE - 137 kJ
therefore,
ΔE = (130 + 137 ) kJ
ΔE = 167 kJ
Therefore, the change in energy of the gas mixture during the reaction is 167 kJ.
Since the value of energy change Is positive, therefore this Is endothermic reaction
Heat of vaporization of water = 540 cal/g
m=1000 g
energy supplied = 5.4 kcal=5400 cal
T1=T2=100 deg. C
so all energy is used to convert to steam
mass of steam produced = 5400 cal /(540 cal/g)
=5400/540 cal *g/cal
=10 g
Answer:
18.02 g/mol
Explanation:
Add the atomic mass of the parts of H2O
1.01 + 1.01 + 16 = 18.02
H H O
Something that breaks with little force against it.
Answer:
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