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Cloud [144]
2 years ago
6

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0​

Mathematics
2 answers:
morpeh [17]2 years ago
6 0

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

  • If b² - 4ac > 0 , There are 2 real-number solutions

  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

  • a = 1
  • b = 2
  • c = -8

1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

artcher [175]2 years ago
6 0

Answer:

x = 2, - 4

Step-by-step explanation:

The factors of 8 are:

1, 8

2, 4

You can combine 2 and 4 to create 2.

( x - 2 ) ( x + 4 ) = 0

0 can either be x - 2 or x + 4

Therefore, x = 2 or - 4

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Find the equation of the sphere centered at (-9,9, -9) with radius 5. Normalize your equations so that the coefficient of x2 is
olganol [36]
<h2><u>Answer</u>:</h2>

(a) x² + y² + z² + 18(x - y + z) + 218 = 0

(b) (x + 9)² + (y - 9)² + 56 = 0

<h2><u>Step-by-step explanation:</u></h2>

<em>The general equation of a sphere of radius r and centered at C = (x₀, y₀, z₀) is given by;</em>

(x - x₀)² + (y - y₀)² + (z - z₀)² = r²               ------------------(i)

<em>From the question:</em>

The sphere is centered at C = (x₀, y₀, z₀) = (-9, 9, -9) and has a radius r = 5.

<em>Therefore, to get the equation of the sphere, substitute these values into equation (i) as follows;</em>

(x - (-9))² + (y - 9)² + (z - (-9))² = 5²

(x + 9)² + (y - 9)² + (z + 9)² = 25      ------------------(ii)

<em>Open the brackets and have the following:</em>

(x + 9)² + (y - 9)² + (z + 9)² = 25

(x² + 18x + 81) + (y² - 18y + 81) + (z² + 18z + 81) = 25

x² + 18x + 81 + y² - 18y + 81 + z² + 18z + 81 = 25

x² + y² + z² + 18(x - y + z) + 243 = 25

x² + y² + z² + 18(x - y + z) + 218 = 0    [<em>equation has already been normalized since the coefficient of x² is 1</em>]

<em>Therefore, the equation of the sphere centered at (-9,9, -9) with radius 5 is:</em>

x² + y² + z² + 18(x - y + z) + 218 = 0

(2)  To get the equation when the sphere intersects a plane z = 0, we substitute z = 0 in equation (ii) as follows;

(x + 9)² + (y - 9)² + (0 + 9)² = 25

(x + 9)² + (y - 9)² + (9)² = 25

(x + 9)² + (y - 9)² + 81 = 25        [<em>subtract 25 from both sides</em>]

(x + 9)² + (y - 9)² + 81 - 25 = 25 - 25

(x + 9)² + (y - 9)² + 56 = 0

The equation is therefore, (x + 9)² + (y - 9)² + 56 = 0

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