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Rudik [331]
1 year ago
9

How much heat is required to melt 22g piece of ice at -8 degrees to water at 14 degrees? (I'm stuck on the steps to solve.)

Chemistry
1 answer:
Alex Ar [27]1 year ago
7 0

The amount of heat that  is required to melt 22g piece of ice at -8 degrees to water at 14 degrees is 1,011.56 Joules.

<h3>How do we calculate the required heat?</h3>

Required amount of heat will be calculated by using the below equation as:

Q = mcΔT, where

m = mass = 22g

c = specific heat of ice = 2.09 J/g. degree C

ΔT = change in temperature = 14 - (-8) = 22 degree C

On putting all values, we get

Q = (22)(2.09)(22) = 1,011.56 J

Hence required amount of heat is 1,011.56 J.

To know more about required heat, visit the below link:

brainly.com/question/16462083

#SPJ1

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<h3>Reducing agent</h3>

A reducing agent is a chemical species that "donates" one electron to another chemical species in chemistry (called the oxidizing agent, oxidant, oxidizer, or electron acceptor). Earth metals, formic acid, oxalic acid, and sulfite compounds are a few examples of common reducing agents.

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Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa
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Answer:

Explanation:

Since it first order, we use order rate equation

In ( \frac{A1}{A0}) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)

also, t half life = \frac{In2}{k} where k is rate constant

k = \frac{In 2}{45 days} = 0.0154

In ( \frac{0.8}{1}) = - 0.0154 t

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