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1 year ago

How much heat is required to melt 22g piece of ice at -8 degrees to water at 14 degrees? (I'm stuck on the steps to solve.)

1 answer:

7 0

The amount of heat that is required to melt 22g piece of ice at -8 degrees to water at 14 degrees is 1,011.56 Joules.

<h3>How do we calculate the required heat?</h3>

Required amount of heat will be calculated by using the below equation as:

Q = mcΔT, where

m = mass = 22g

c = specific heat of ice = 2.09 J/g. degree C

ΔT = change in temperature = 14 - (-8) = 22 degree C

On putting all values, we get

Q = (22)(2.09)(22) = 1,011.56 J

Hence required amount of heat is 1,011.56 J.

To know more about required heat, visit the below link:

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3 years ago

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2.74 M

Explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

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Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

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