Answer:
51.17g of Cl2O7
Explanation:
The equation for the reaction is given below:
Cl2O7 + H2O → 2HClO4
First, let us calculate the masses of Cl2O7 and HClO4 from the balanced equation. This is illustrated below:
Molar Mass of Cl2O7 = (2x35.5) + (16x7) = 71 + 112 = 183g/mol
Molar Mass of HClO4 = 1 + 35.5 + (16x4) = 1 + 35.5 + 64 = 100.5g/mol
Mass of HClO4 from the balanced equation = 2 x 100.5 = 201g
Now, we can obtain the mass of Cl2O7 that must react to form 56.2g HClO4. This is illustrated below:
From the equation above,
183g of Cl2O7 reacted to produced 201g of HClO4.
Therefore, Xg of Cl2O7 will react to produce 56.2g of HClO4 i.e
Xg of Cl2O7 = (183 x 56.2)/201
Xg of Cl2O7 = 51.17g
From the calculations made above, 51.17g of Cl2O7 is required to produce 56.2g of HClO4
Answer:
The repeating nature of physical and chemical properties with atomic number
Explanation:
Periodic table is designed in a way in which elements are divided in groups and periods. Periods are rows and groups are columns. The elements in groups share similar properties due to the same number of valence electrons they have. Going along each period, we'll always get back to the same group at some point. This is why we have periodic trends, the trends repeat gradually when we finally reach the same group we're analyzing.
Physical and chemical properties vary periodically. For example:
- atomic radius decreases from left to right along the period;
- ionization energy increases from left to right along the period;
- electronegativity increases from left to right along the period;
- metallic properties decrease from left to right along the period.
The first answer or “t” :)
<span>As the amount of water vapor in the air increases, the relative humidity increases.</span>
Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa