1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrews [41]
3 years ago
10

. Which of the following statements best describes the relationship between elements and compounds?

Chemistry
1 answer:
vampirchik [111]3 years ago
8 0
I think the answer is A
You might be interested in
Why do you think the Na+ ion is smaller than a neutral Na atom? Why do you think the Cl - ion is larger than a neutral Cl atom?
Sphinxa [80]

Answer:

Na+ ion is smaller than a neutral Na atom in the ion there was one more proton which will attract electron bring it closer to the center making the atomic radius smaller. Therefore making a Na+ ion is smaller than a neutral Na atom Explanation:

yes

7 0
3 years ago
What domain is an onion
Nana76 [90]
The domain that is an onion is the <span>Eukaryote.

</span>
3 0
3 years ago
Read 2 more answers
How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of formula units of Sr(HCO_3)_2=4.55\times 10^{15}

As, 6.022\times 10^{23}  number of formula units are contained in 1 mole of a substance.

So, 4.55\times 10^{15} number of formula units will be contained in = \frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

5 0
3 years ago
What is the relationship between producers and consumers in a food chain a producers eat consumers b consumers eat producers c p
allochka39001 [22]

Answer:

b consumers eat producers

Explanation:

In a food chain, the consumers are living organisms that eat organisms from a different population. Examples are herbivores like goats.

Producers make their own food in the food chain. Examples are plants.

The relationship between consumer and producers is hence that consumers consume / eat producers. Goats eat grass.

The correct option is;

b consumers eat producers

3 0
2 years ago
How many moles of LiOH are needed to react completely with 25.5 g of CO2
LekaFEV [45]

Answer:

3.18 mol

Explanation:

2LiOH+CO_{2}-> Li_{2}CO_{3} +H_{2}O

n(CO2) = mass/ Mr.

             = 25.5 / 16

             = 1.59 mol

As per the equation above,

n(LiOH) : n(CO2)

     2      :    1

∴  3.18   :  1.59

     

3 0
2 years ago
Other questions:
  • Na (atomic no. 11) reacts with Cl (atomic no. 17) to become stable. In the reaction, Na will ____________, while Cl will _______
    7·1 answer
  • In an organism, the brain directs the body how to respond to stimuli from the environment. In a cell, this function is performed
    7·1 answer
  • How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10?
    6·1 answer
  • I need heLp ASAP
    7·2 answers
  • The decomposition of ammonia is: 2 NH3(g) ? N2(g) + 3 H2(g). If Kp is 1.5 × 103 at 400°C, what is the partial pressure of ammoni
    7·1 answer
  • Cuando los volcanes entran en erupción lanzan al exterior porciones de materia muy variada ¿cuales fueron los productos de la er
    10·1 answer
  • What influences the movement of ions and molecules?
    13·2 answers
  • The heat flux, or the rate of heat transfer per unit area, is measured in watts (Watts) only A. TRUE B. FALSE
    6·1 answer
  • 19. When 0.5g of calcium trioxocarbonate (IV) was added to excess dilute
    6·1 answer
  • Answer the question please
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!