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2 years ago

In 25 words or fewer, what do you think a scientist would want to explain about this soda?

Chemistry

1 answer:

Gnesinka [82]2 years ago

8 0

Answer:

This soda is brown, sweet, has high carbonation, and is about 200 calories when consumed.

Explanation:

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Complete combustion of 5.90 g of a hydrocarbon produced 19.2 g of CO2 and 5.89 g of H2O. What is the empirical formula for the h

scZoUnD [109]

$44g \ CO_{2} \ \ \ \rightarrow \ \ 12g \ C\\
19,2g \ CO_{2} \rightarrow \ \ \ x\\\\
x=\frac{19,2g*12g}{44g}\approx5,24g \ \ \ \Rightarrow \ \ n=\frac{5,24g}{12\frac{g}{mol}}\approx0,44mol\\\\\\
18g \ H_{2}O \ \ \ \rightarrow \ \ \ 2g \ H\\
5,89g \ H_{2}O \ \rightarrow \ \ y\\\\
y=\frac{5,89g*2g}{18g}\approx0,65g \ \ \ \ \Rightarrow \ \ n=\frac{0,65g}{1\frac{g}{mol}}=0,65mol\\\\\\
n_{C}:n_{H}=0,44:0,65\approx1:1\\\\
CH$

4 0

3 years ago

Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the

jok3333 [9.3K]

Answer: The average of the densities of the given measurements is 1.363 g/mL

Explanation:

The equation used to calculate density of a substance is given by:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

First measured value of density, $d_1$ = 1.019 g/mL

Second measured value of density, $d_2$ = 1.498 g/mL

Third measured value of density, $d_3$ = 1.572 g/mL

Putting values in above equation, we get:

$\rho_{mix}=\frac{d_1+d_2+d_3}{3}$

$\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL$

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0

2 years ago

If you had 1.50 g of ZnSO4.7H20, zinc sulfate septahydrate, how many grams of water will there be?

MariettaO [177]

Answer:

There will be 1.50 gram of water

5 0

2 years ago

A covalent compound that shares two pairs of electrons. What is it?

Nitella [24]

The two oxygen atoms share two pairs of electrons, so two covalent bonds hold the oxygen molecule together

3 0

3 years ago

What type of front in which warm air mass is cut off from the ground by cool air beneath it?

vodomira [7]

Answer:

Occluded Front

Explanation:

"Occluded Front Forms when a warm air mass gets caught between two cold air masses. The warm air mass rises as the cool air masses push and meet in the middle. The temperature drops as the warm air mass is occluded, or “cut off,” from the ground and pushed upward."

- www.eduplace.com › science › hmxs › pdf

7 0

2 years ago