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Oksanka [162]
3 years ago
7

What are the two main phases of cell division

Chemistry
1 answer:
Digiron [165]3 years ago
8 0

Answer:

Mitosis meiosis

Explain:

Mitosis is where the cell splits into 2 more cells (diploid)

Meiosis is where the cell splits into 2, and then split again, making 4 (haploid)

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Please help! it’s due date is in a few minutes
Licemer1 [7]

Answer:

40'0'

Explanation:

X is smaller than |-40|

7 0
2 years ago
Which objects cannot be observed in detail without a microscope?
Sonbull [250]

The objects which cannot be observed in detail without a microscope

include the following:

  • Red blood cell
  • Bacterium

<h3>What is a Microscope?</h3>

A microscope is an instrument which is used to view smaller objects such as

microbe,cells, tissues etc. This instrument is used in viewing the different

cells found in the body as they can't be seen with the eye.

The remaining options which can be seen with the eyes don't require

the use of microscopes.

Read more about Microscope here brainly.com/question/25268499

3 0
2 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
Which of the following is part of the central nervous system?
OLga [1]

The brain is part of the central nervous system.

Nerves and sensors are part of the peripheral nervous system. Only the brain and spinal cord make the central nervous system.

3 0
3 years ago
Read 2 more answers
N
bazaltina [42]

Answer:

electron - proton

Explanation:

fsger

5 0
3 years ago
Read 2 more answers
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