See attachment file below.
Answer: 11/3
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Answer:
Two
Explanation:
The solution of a system of equations is defined as the values which satisfies both equations.
Graphically, the solutions are represented by the points of intersection between the two equtaions.
In the given graph, we have a circle and a line, we can note that these two intersect in two points.
This means that the system has two solutions
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<h3>
Answer: Choice B) real and integer</h3>
Explanation:
The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} basically its the set of positive and negative whole numbers, including 0 as well. The set of whole numbers is {0, 1, 2, 3, 4, ...} so any positive number that does not a fractional or decimal part. The value 0 is included in the set of whole numbers. The natural numbers is {1, 2, 3, 4, ...} so it is the set of whole numbers but we kicked out 0 from this set. The set of natural numbers is also called the set of counting numbers.
If we take any two integers and divide them then you'll get a rational number. You cannot have zero in the denominator, but you can have any other integer. For example, 2 and 3 divide to get the fraction 2/3 which is a rational number. Numbers that we cannot express as a fraction of two integers are said to be irrational. An example of this is pi = 3.14 which is irrational. We cannot write pi as a ratio of two integers. One approximation is pi = 22/7, but this doesn't represent pi exactly. Any integer itself is rational. Something like -13 can be written as -13/1, so we cannot say -13 is irrational. That rules out choice A. Choice C is ruled out because negative numbers aren't natural numbers. The same can be said about -13 not being part of the whole number set {0, 1, 2, 3, 4, ...} so choice D is also false.
Are you sure this is college mathimatics bec this doesn't look like it
