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2 years ago

5

Is 2 1/5 × 1 1/4 greater, equal, or less than 1 1/4

1 answer:

Zielflug [23.3K]2 years ago

3 0

Answer:

2 1/5 x 1 1/4 is greater than 1 1/4

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For the most recent seven years, the U.S. Department of Education reported the following number of bachelor's degrees awarded in

bixtya [17]

Answer: 8327

Step-by-step explanation:

The arithmetic mean of a data is given by :_

$\dfrac{\text{Sum of observations}}{\text{Number of observations}}\\\\=$

Given : For the most recent seven years, the U.S. Department of Education reported the following number of bachelor's degrees awarded in computer science: 4,033; 5,652; 6,407; 7,201; 8,719; 11,154; 15,121.

Then, the annual arithmetic mean number of degrees awarded will be :-

$\dfrac{4033+5652+6407+7201+8719+11154+15121}{}\\\\=\dfrac{58287}{7}\\\\=8326.71428571\approx8327$

Hence, the annual arithmetic mean number of degrees awarded = 8327

8 0

3 years ago

Explain how to fin 4 x 80. show your work

algol [13]

4x80=320

Work:

4x8 = 32
(4+4+4+4+4+4+4+4)
Now carry the 0 and you get 320

5 0

2 years ago

HELP ME PLEASEE ASAP

beks73 [17]

Answer:

Im pretty sure its the first one.

Step-by-step explanation:

3 0

3 years ago

Sonny deposited $8,500 in an account that earns 4% simple interest. If Sonny makes no more deposits or withdrawals, then how muc

SashulF [63]

Answer: $680.00

Step-by-step explanation:

Principal= 8500

Rate= 4%

Time= 2 years

Interest= (Principal×Rate×Time)/100

= (8500×4×2)/100

= 68000/100

= $680

The interest is $680

5 0

3 years ago

Read 2 more answers

Given that y=c1e3t+c2e−3t a solution to the differential equation y′′−9y=0, where c1 and c2 are arbitrary constants, find a func

evablogger [386]

Answer:

$y = 7e^{-3t}$

Step-by-step explanation:

$y = C_1e^{3t} + C_2e^{-3t}$

$y(0) = 7$ implies that when $t=0$ , $y=7$ .

$7 = C_1e^{3\times0) + C_2e^{-3\times0}$

$7 = C_1+C_2$

For the condition $\lim\limits_{t \to +\infty} y(t) = 0$ , as $t\to+\infty$ , $y\to0$ .

In the expression for $y$ , as $t\to+\infty$ , the term containing $C_2$ vanishes. Hence,

$0 = C_1e^{3t}$

$C_1 = 0$

Since $7 = C_1+C_2$

$7 = 0+C_2$

$C_2 = 7$

Substituting for $C_1$ and $C_2$ in $y$ ,

$y = 7e^{-3t}$

5 0

3 years ago